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Vikki [24]
3 years ago
6

12) m 1) MZHGF = 16x + 4, mZEGF= 110°, and mZHGE = 3x + 11. Find x. G H

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

5 = x

Step-by-step explanation:

Since we are not given a midpoint, we use the Angle Addition Postulate:

110 = [3x + 11] + [16x + 4]

110 = 15 + 19x

- 15 - 15

_______________

95 = 19x

___ ___

19 19

5 = x

110 = [3[5] + 11] + [16[5] + 4]

15 80

110 = 110 ☑

Therefore, 5 = xis a genuine statement.

I am joyous to assist you anytime.

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3 years ago
| 3x - 5|= 11<br> How do u do this
Valentin [98]

Answer:

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Step-by-step explanation:

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3 years ago
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Mrac [35]

Answer:

m =  \dfrac{3}{4}

Step-by-step explanation:

We would like to find the <u>s</u><u>l</u><u>o</u><u>p</u><u>e</u><u> </u> of the line of the given equation .

\longrightarrow y =\dfrac{3}{4}x -1

We know that <u>s</u><u>l</u><u>o</u><u>p</u><u>e</u><u> </u><u>i</u><u>n</u><u>t</u><u>e</u><u>r</u><u>c</u><u>e</u><u>p</u><u>t</u><u> </u><u>f</u><u>o</u><u>r</u><u>m</u><u> </u> of the line is given by ,

\longrightarrow y = mx + c

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  • m is the slope
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Now we can compare the given equation with the slope intercept form to find the slope . You will see that 3/4 is present at the place of m .Therefore ,

\longrightarrow \underline{\underline{m=\dfrac{3}{4}}}

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4 0
2 years ago
Find the transition matrix from B to B'. B = {(-1,2), (3, 4)), B' = {(1, 0), (0, 1)} STEP 1: Begin by forming the following matr
8_murik_8 [283]

Answer:  The required matrix is

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

Step-by-step explanation:  We are given to find the transition matrix from the bases B to B' as given below :

B = {(-1,2), (3, 4)) and B' = {(1, 0), (0, 1)}.

Let us consider two real numbers a, b such that

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Therefore, the transition matrix is given by

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Thus, the required matrix is

T=\left[\begin{array}{ccc}-1&3\\2&4\end{array}\right] .

7 0
3 years ago
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