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kaheart [24]
3 years ago
9

Find the distance between the two points: (-16,5) and (3,5)

Mathematics
2 answers:
bezimeni [28]3 years ago
7 0
The distance is 19

Learned this in math btw

Hope this helps a lot :D
egoroff_w [7]3 years ago
4 0

The distance is 19

Hope this helps! :D

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There are 12 books on a shelf 5 of these books are new the rest are used what is the ratio of new books to used books
tiny-mole [99]

Answer:

5:7

Step-by-step explanation:

Basically you first find the amount of the books are the shelf knowing that you have 5 new books, you subtract the amount of new books from total books. And 5:7 can't be simplified any further making 5:7 the answer.

5 0
3 years ago
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Parker rolled a number cube 50 times the three appeared 12 times what is the experimental probability of rolling a 3
horsena [70]
12/50 is the probability of rolling a 3
12/50= He has a 24% chance of rolling a three
3 0
3 years ago
Madilyn and Penelope have 28 toys to build. Madilyn builds 3/4 of the toys, while Penelope builds 1/7. How many toys are there l
uysha [10]

Answer:

Step-by-step explanation:

3/4 x 28=21   Madilyn built 21 toys.

1/7 x 28=4     Penelope built 4 toys.

21+4=25        25 toys have been built altogether.

28-25=3

There are 3 toys left to build.

3 0
3 years ago
PLEASE HELP I WILL GIVE YOU POINTS,BRAINLIEST, AND A COOKIE !!
Anna007 [38]

Answer:

20 maybe

Step-by-step explanation:

6 0
3 years ago
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A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p
Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, H_0 : p \leq 0.29  {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, H_1 : p > 0.29  {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

          T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = proportion of chips that do not fail in the first 1000 hours of their use = 32%

            n = sample of chips = 1500

So, <u>test statistics</u> = \frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }

                              = 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0
3 years ago
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