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3 years ago

Simplify the fraction to lowest teems 10/25=

Mathematics

2 answers:

zimovet [89]3 years ago

8 0

Answer:

2/5

Step-by-step explanation:

10 divided by 5 is 2

25 divivded by 5 is 5

fgiga [73]3 years ago

8 0

2/5, divide both by 5

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Help I have to turn these in fast I'll give brainliest

____ [38]

Answer:

<h3><u>Firs</u><u>t</u><u> </u><u>q</u><u>uestion</u></h3>

To find ? we use sine

sin ∅ = opposite / hypotenuse

From the question

The hypotenuse is 50

The opposite is 25

So we have

sin ? = 25 / 50

sin ? = 1/2

? = sin-¹ 1/2

<h3><u>Sec</u><u>ond</u><u> </u><u>q</u><u>uestion</u></h3>

To find ? we use tan

tan ∅ = opposite / adjacent

From the question

the opposite is 8

the adjacent is 33

So we have

tan ? = 8/33

? = tan-¹ 8/33

? = 13.62

<h3>? = 14° to the nearest degree</h3>

Hope this helps you

3 0

3 years ago

For all values of x, f(x)=2x^2 and g(x)= x+1<br> Solve fg(x) = gf(x)

Andrej [43]

Answer:

-0.25

Step-by-step explanation:

→ Find fg(x)

2 ( x + 1 )² = 2x² + 4x + 2

→ Find gf(x)

2x² + 1

→ Equate them

2x² + 1 = 2x² + 4x+ 2

→ Move everything to the right hand side

0 = 4x + 1

→ Solve

x = -0.25

4 0

2 years ago

Read 2 more answers

Find the distance between the points (4,-2) and (0,10)

vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: $\sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}}$ We can now put in values and solve.

$\sqrt{(4-0)^{2} + (-2-10)^{2}}$

$\sqrt{16 + 144}$

$\sqrt{160}$

3 0

3 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

3 years ago

Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
$\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } }$
Reduce the fraction one more time with $y^{6}$ .
$\sqrt{ \frac{5}{ x^{4} y^{2} } }$
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
$\frac{ \sqrt{5} }{ x^{2} y}$
Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
Let me know if you have any further questions.
:)

3 0

3 years ago

Read 2 more answers