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2 years ago

What is the derivative of y=3tan(x)y=3 tan (x) ?

Mathematics

2 answers:

maw [93]2 years ago

6 0

$y=3tanx\\\\tanx=\frac{sinx}{cosx}\Rightarrow y=\frac{3sinx}{cosx}\\\\\\y'=\frac{(3sinx)'cosx-3sinx(cosx)'}{(cosx)^2}=\frac{3cosxcosx-3sinx(-sinx)}{cos^2x}=\frac{3cos^2x+3sin^2x}{cos^2x}\\\\=\frac{3(cos^2x+sin^2x)}{cos^2x}=\frac{3(1)}{cos^2x}=\frac{3}{cos^2x}\\\\-------------------\\\\sin^2x+cos^2x=1$

viva [34]2 years ago

6 0

Answer is in the attachment below. Use the "product rule".

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ASAP PLEASE!!!!

Mashutka [201]

Answer: 74

Step-by-step explanation:

8 0

3 years ago

38÷244 ,24÷943,653÷52

jeka94

38/244= about 0.16
24/943= about 0.03
653/53= about 12.32
All answers are rounded

5 0

3 years ago

I have to get this so I pass help plz

pshichka [43]

Answer:

$\boxed{\sf x=-2}$

$\boxed{\sf y=-4}$

Step-by-step explanation:

First, Let's solve for x in -2x+2y=-4:

$\sf -2x+2y=-4$

Subtract 2y from both sides:

$\sf -2x+2y-2y=-4-2y$

$\sf -2x=-4-2y$

Divide both sides by -2:

$\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}$

$\bold{ x=y+2}$

Now, we'll substitute x=y+2 to 3x+3y=-18:

$\sf 3x+3y=-18$

→ let x=2+y

$\sf 3\bold{(2+y)}+3y=-18$

Simplify:

$\sf 6+6y=-18$

Now, let's solve for y in 6+6y=-18

$\sf 6+6y=-18$

Subtract 6 from both sides:

$\sf 6+6y-6=-18-6$

$\sf 6y=-24$

Divide both sides by 6:

$\sf \cfrac{6y}{6}=\cfrac{-24}{6}$

$\bold{ y=-4}$

Now, substitute y=-4 into x=2+y:

$\sf x=2+y$

→ let y = -4

$\sf x=2+\bold{-4}$

$\bold{x=-2}$

Therefore, x=-2 and y=-4.

_____________________________________

5 0

1 year ago

Help me with this please

Angelina_Jolie [31]

It’s the last one. b < c < a

4 0

2 years ago

What is the slope of o line that passes through (-4,-14) and (19,11)?

DerKrebs [107]

Answer:

D, see description below.

There is a possible typo in the problem since these points have slope 25/23.

Step-by-step explanation:

To find the slope of a line, calculate the distance between points with a ratio of vertical to horizontal distance. This is done using the formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Here the points are (-4,-14) and (19,11). Substitute and simplify.

$m=\frac{11--14}{19--4}=\frac{11+14}{19+4}=\frac{25}{23}$

I think there is a typo in your points (-4,-14) and (19,11) because the answer doesn't align to the answer choices. But based on them, I would answer D or 24/23 since it's the closest value.

6 0

3 years ago