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JulijaS [17]
2 years ago
10

Please help before 12:40!! * locate all items* be specific on which is which thanks

Mathematics
2 answers:
larisa86 [58]2 years ago
8 0

Answer:

item 1: (-3,3.5),

item 2: (3,1)

Item 3: (-1,-2.5)

item 4: (1.8,-1)

Step-by-step explanation:

oksano4ka [1.4K]2 years ago
3 0
Item 1: (-3, 3.5)

Item 2: (3,1)

Item 3:(-1,-2.5)

Item4:(1.8, -1 )
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Factor 15c·(a+b)+8·(b+a)
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(15c + 8)(a + b).

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15c·(a+b)+8·(b+a)

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Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
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D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

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