Please help before 12:40!! * locate all items* be specific on which is which thanks
2 answers:
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Answer:
Step-by-step explanation:
Question 8
Let the equation of a line passing through two points and
is given by,
y = mx + b
Here, m = slope and y-intercept = b
Since, m =
For two points (1, 4) and (5, 8),
m =
m = 1
Equation will be,
y = (1)x + b
y = x + b
Since, this line passes through (1, 4),
4 = 1 + b
b = 3
Therefore, equation of the line will be,
y = x + 3
Question 9
Let the equation is y = mx + b
m =
For two points (2, 10) and (6, 4)
m =
m =
By substituting the value of 'm' in the equation,
y =
Since, this line passes through (2, 10)
10 =
b = 10 + 2
b = 12
Therefore, equation of the line will be,
9514 1404 393
Answer:
- maximum: 2
- minimum: -6
Step-by-step explanation:
The extrema will be at the ends of the interval or at a critical point within the interval.
The derivative of the function is ...
f'(x) = 3x² -4x -4 = (x -2)(3x +2)
It is zero at x=-2/3 and at x=2. Only the latter critical point is in the interval. Since the leading coefficient of this cubic is positive, the right-most critical point is a local minimum. The coordinates of interest in this interval are ...
f(0) = 2
f(2) = ((2 -2)(2) -4)(2) +2 = -8 +2 = -6
f(3) = ((3 -2)(3) -4)(3) +2 = -3 +2 = -1
The absolute maximum on the interval is f(0) = 2.
The absolute minimum on the interval is f(2) = -6.
