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ddd [48]
3 years ago
14

How do ocean currents on the water's surface transfer energy?

Physics
1 answer:
Anit [1.1K]3 years ago
6 0
Exactly what the first person said. Hope this helps!
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The energy released during a nuclear reaction is a result of
astra-53 [7]

Answer:

the conversion of matter into energy

Explanation:

A nuclear reaction is a reaction in which there is a change in the nuclei of the atoms involved. The two most important examples of nuclear reactions are:

- Nuclear fission: it occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei

- Nuclear fusion: it occurs when two lighter nuclei fuse together into a heavier nucleus

In both cases, the total mass of the final products is smaller than the total mass of the initial nuclei: this means that part of the mass of the initial nuclei has been converted into energy, according to Einstein's formula:

E=\Delta m c^2

where \Delta m is the variation of mass and c is the speed of light. Since the value of c is very large, we can see from the formula that even a small amount of \Delta m is able to produce a huge amount of energy, and this is a typical feature of any nuclear reaction.

8 0
3 years ago
Estimate the smallest possible period of a satellite in a circular orbit around earth. (mass and radius of earth is 5.98 x 1024
myrzilka [38]
Given: Mass of earth Me = 5.98 x 10²⁴ Kg

           Radius of earth r = 6.37 x 10⁶ m

            G = 6.67 x 10⁻¹¹ N.m²/Kg²

Required: Smallest possible period T = ?

Formula: F = ma;  F = GMeMsat/r²     Centripetal acceleration ac = V²/r

               but V = 2πr/T

equate T from all equation.

F = ma

GMeMsat/r² = Msat4π²/rT²    

GMe = 4π²r³/T²

T² = 4π²r³/GMe  

T² = 39.48(6.37 x 10⁶ m)³/6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 1.02 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 25,563,909.77 s²

T = 5,056.08 seconds    or around   1.4 Hour

3 0
3 years ago
A car starts from rest at a stop sign. It accelerates at 2.0 m/s2 for 6.2 seconds, coasts for 2.5 s , and then slows down at a r
BigorU [14]

Answer:

the distance between the stop signs is 120.7 m.

Explanation:

The car moved in three stages;

(1) It accelerates from rest at 2.0 m/s² for 6.2 seconds

(2) it moved at a constant speed for 2.5 s

(3) it finally decelerate at the rate of 1.5m/s²

(1) The distance moved by the car during the first stage;

s₁ = ut + ¹/₂at²

s₁ = 0 + ¹/₂ (2)(6.2)²

s₁ = 38.44 m

(2) The distance moved by the car during the second stage;

calculate the constant speed of the car,

v = u + at

v = 0 + 2 x 6.2

v = 12.4 m/s

The distance moved by the  car as it coasts for 2.5s: s₂ = vt

s₂ = 12.4 x 2.5

s₂ = 31 m

(3) The distance moved by the car during the third stage;

When the car stops, the final velocity is zero.

v² = u² + 2as₃

a = -1.5 m/s², since the car slowed down or decelerated.

0 = 12.4² + (2 x - 1.5)s₃

0 = 153.76 - 3s₃

3s₃ = 153.76

s₃ = 153.76 / 3

s₃ = 51.253 m

The total distance moved by the car from the start to stop = s₁ + s₂ + s₃

d = 38.44 m + 31 m + 51.253 m

d = 120.7 m

Therefore, the distance between the stop signs is 120.7 m.

8 0
3 years ago
If a car can go from 0 to 60mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50m
Helga [31]
The answer would be <span>87.5 mi/hr</span>
4 0
3 years ago
How do plants respond to heat light and energy?
zloy xaker [14]
Plants are very sensitive creature therefore responds to any thing that comes its way ,therefore the way they respond to heat light and energy in the same proportion because they work together in helping plants manufacture their own food through the process of photosynthesis
8 0
3 years ago
Read 2 more answers
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