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Kamila [148]
3 years ago
5

You walked a line 100 meters north, then 100 meters west, then 100 meters south. Which is true?

Physics
1 answer:
dangina [55]3 years ago
7 0

Answer:

distance is 300 m and displacement is 100 m

Explanation:

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A gas mixture contains 320mg methane, 175 mg argon, 225 mg nitrogen (N2). The partial pressure of argon at 300K is 12.52 kPa. Wh
svet-max [94.6K]

<u>Answer:</u> The volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For methane:</u>

Given mass of methane = 320 mg = 0.3 g     (Conversion factor:  1 g = 1000 mg)

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane}=\frac{0.3g}{16g/mol}=0.019mol

  • <u>For argon:</u>

Given mass of argon = 175 mg = 0.175 g

Molar mass of argon = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of argon}=\frac{0.175g}{40g/mol}=0.0044mol

  • <u>For nitrogen:</u>

Given mass of nitrogen = 225 mg = 0.225 g

Molar mass of nitrogen = 28 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen}=\frac{0.225g}{28g/mol}=0.0080mol

To calculate the volume of the mixture, we use the equation:

PV = nRT         ......(2)

We are given:

Partial pressure of argon = 12.52 kPa

Temperature = 300 K

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

n = number of moles of argon = 0.0044 moles

Putting values in equation 2, we get:

12.52kPa\times V=0.0044mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\V=\frac{0.0044\times 8.31\times 300}{12.52}=0.876L

Now, calculating the total pressure of the mixture by using equation 2:

Total number of moles = [0.019 + 0.0044 + 0.0080] mol = 0.0314 mol

V= volume of the mixture = 0.876 L

Putting values in equation 2, we get:

P\times 0.876L=0.0314mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times 300K\\\\P=\frac{0.0341\times 8.31\times 300}{0.876}=89.36kPa

Hence, the volume and total pressure of the mixture is 0.876 L and 89.36 kPa respectively.

5 0
3 years ago
Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic
rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x 10^{-5} T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = \frac{U_{o}I }{2\pi r}

where: I is the current, r is the distance between the wires and U_{0} is the magnetic field constant.

But, I = 11 A, r = 0.12 m and U_{0} = 4\pi x 10^{-7} Tm/A

So that;

B = \frac{4\pi *10^{-7}*11 }{2\pi *0.12}

   = 1.8333 x 10^{-5}

B = 1.83 x 10^{-5} T

6 0
3 years ago
How many kids under the age of 21 are drinking and smoking in the us and California combined
prohojiy [21]

Answer:

Well I don't think there is a specific answer for that, but a lot of under the age children do drink and smoke,because these days,their parents either don't care, and some just don't know about it. Many kids drink and smoke these days and I don't think there is a on point percentage.

Explanation: Hope this helps and have a good day!!!

4 0
2 years ago
Read 2 more answers
A ball has a mass of 140 g what is the force needed to accelerate the mall at 25 m/s squared
IRISSAK [1]
3.5 Newton of force is needed to accelerate 140g of ball at 25 m/s^2 using the formula f=ma
Change 140g to kg
8 0
3 years ago
Read 2 more answers
Two 100kg bumper cars are moving towards eachother in oppisite directions. Car A is moving at 8 m/s and Car B at -10 m/s when th
DerKrebs [107]

Answer:

-10 m/s

Explanation:

When two cars collide then the momentum of two cars will remains conserved

  • Mass of two cars = 100 kg
  • Speed of car A = 8 m/s
  • Speed of car B = - 10 m/s
  • After collision the speed of car B = +8 m/s

By momentum conservation equation

               m1v1i+m2v2i=m1v1f + m2v2f

               (100)(8)+(100)(-10)=(100v)+(100)(8)\\                            v=-10 m/s

7 0
3 years ago
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