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anyanavicka [17]

4 years ago

7

Find the missing value in the equivalent ratio 18:27 = 16:

1 answer:

Nady [450]4 years ago

8 0

Answer:

24

Step-by-step explanation:

$\frac{16}{27} = \frac{16 }{x}$

$\frac{2}{3 } = \frac{16}{x}$

$2x = 16 \times 3$

$2x = 48$

$x = 48 \div 2$

$x = 24$

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kodGreya [7K]

To equally divide the pizzas, let's use a similar point to base on the remaining pizzas. On the first pizza 1/12 was not eaten an the other was 2/4. Use 12 as the base parts. 1/12 +2/4. 2/4 is equal to 1/2, so let's used 6/12 (also 1/2) to replace 2/4 to add both fractions. 1/12+6/12=7/12.

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Which value is equivalent to the expression 23 + 34? A) 18 B) 72 C) 78 D) 89

Darya [45]

Answer:

none

Step-by-step explanation:

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Nana76 [90]

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Zolol [24]

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There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0

3 years ago