Given:
μ = 89 ng/ml, population mean
σ = 23 ng/ml, population standard deviation
Random variable, x = 100
To test P(x < 100), calculate the z-score.
z = (x-μ)/σ = (100 - 89)/23 = 0.4783
From standard tables, obtain
P(x < 100) = 0.6838 = 68.4%
Answer: 68.4%
Answer:
594
Step-by-step explanation:
You multiply 18 by 3 by 11 :)
R = 40.5 m
C = 254.46900494077 m
A = 5152.9973500507 m<span>2</span>
