Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8
Answer:
Every week, the mass of the sample is multiplied by a factor of 0.81
Step-by-step explanation:
Let's rewrite the base and find the expression whose exponent is just ttt.
(0.97)7t+5=(0.97)7t⋅(0.97)5=(0.977)t⋅(0.97)5
Therefore, we can rewrite the modeling function as follows.
M(t)=(0.97)5⋅(0.977)t
According to this model, the mass of the sample is multiplied by 0.977 every week. Rounding this to two decimal places, we get 0.977≈0.81.
Answer:
(-infinity, infinity)
Step-by-step explanation:
I assume it's y = 2x-6 which is a linear function. The line goes on forever.
Answer: 829 3/4 or 829 75/100
Step-by-step explanation:
