<h2>A = 0.625</h2>
There are 8 points between 1 and 0 so divide 1 by 8.
1 / 8 = 0.125
Each point has a value of 0.125.
You can minus 0.125 from 1 until you reach A.
Or you can multiple 0.125 by the number of points from 0 to A, including A.
1 - 0.125 - 0.125 - 0.125 = 0.625
0.125 * 5 = 0.625
<h2>A = 0.625</h2>
Answer:
72
Step-by-step explanation:
A full rotation takes 360°. From the picture, it would take 5 rotations to achieve such full degree rotation. Hence, each bit of rotation covers 360°÷5=72°
Answer:
y = 2x-10
Step-by-step explanation:
just that is the way
Answer:
![y=-9](https://tex.z-dn.net/?f=y%3D-9)
Step-by-step explanation:
We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).
Note that x=1 is a <em>vertical line </em>since x is 1 no matter what y is.
This means that if our new line is perpendicular to the old, then it must be a <em>horizontal line</em>.
So, since we have a horizontal line, then our equation must be our y-value of our point.
Our y-coordinate of our point (8,-9) is -9.
Therefore, our equation is:
![y=-9](https://tex.z-dn.net/?f=y%3D-9)
And this is in standard form.
And we're done!
Answer:
![c = 63\\b=21](https://tex.z-dn.net/?f=c%20%3D%2063%5C%5Cb%3D21)
Step-by-step explanation:
Let number of pounds of cans collected by Amy = ![a](https://tex.z-dn.net/?f=a)
Let number of pounds of cans collected by Bruce = ![b](https://tex.z-dn.net/?f=b)
Let number of pounds of cans collected by Carlos = ![c](https://tex.z-dn.net/?f=c)
As per question statement, total number of cans collected = 168
..... (1)
Number of pounds collected by Bruce is
rd of the pounds of cans collected by Carlos.
![b = \dfrac{1}{3}c ..... (2)](https://tex.z-dn.net/?f=b%20%3D%20%5Cdfrac%7B1%7D%7B3%7Dc%20.....%20%282%29)
Number of pounds collected by Amy is equal to number of pounds collected by Bruce and Carlos combined.
Using equation (2):
![a = \dfrac{1}{3}c +c \\\Rightarrow a =\dfrac{4}{3}c ..... (3)](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B1%7D%7B3%7Dc%20%2Bc%20%5C%5C%5CRightarrow%20a%20%3D%5Cdfrac%7B4%7D%7B3%7Dc%20.....%20%283%29)
Using equations (2) and (3) in equation (1), we get:
![\dfrac{4}{3}c+\dfrac{1}{3}c+c =168\\\Rightarrow \dfrac{8}{3}c = 168\\\Rightarrow c =63](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B3%7Dc%2B%5Cdfrac%7B1%7D%7B3%7Dc%2Bc%20%3D168%5C%5C%5CRightarrow%20%5Cdfrac%7B8%7D%7B3%7Dc%20%3D%20168%5C%5C%5CRightarrow%20c%20%3D63)
Using equation (2):
![b = \dfrac{63}{3} = 21](https://tex.z-dn.net/?f=b%20%3D%20%5Cdfrac%7B63%7D%7B3%7D%20%3D%2021)