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Len [333]
2 years ago
13

xy=22 as a proportion please :) It would mean a lot if I could get a fast response! Please explain in detail because I don't get

what it is asking.
Mathematics
2 answers:
fgiga [73]2 years ago
7 0
Xy = 22
1 1


Cross multiply:
xy * 1 = 1 * 22

Simplifying
xy * 1 = 1 * 22

Reorder the terms for easier multiplication:
1xy = 1 * 22

Multiply 1 * 22
1xy = 22

Solving
1xy = 22

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '1y'.
x = 22y-1

Simplifying
x = 22y-1
Fiesta28 [93]2 years ago
3 0
The answer is 22
Have a nice day
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I also need work for understanding on these questions (I will mark as brainliest)
stich3 [128]

Answer:

<em>24000 and 1620 for the first and fifth </em>

Step-by-step explanation:

  • <em>24 x 25 x 40 = 24000</em>
  • <em>9 x 6 x 30 = 1620</em>

<em></em>

<em></em>

<em></em>

  • <em>I only know one and five </em>
  • <em>i couldn't figure out the others</em>
  • <em>Hope this helps</em>
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7 0
3 years ago
For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?
balu736 [363]

Answer:

503 $1 tickets sold.

Step-by-step explanation:

Use two equations  

Let x = number of $1 tickets sold  

Let y = number of $1.50 tickets sold  

x + y = 739  

1x + (1.5)y = 857  

First equation ==> y = 739 - x  

Plug this into the second equation  

x + (1.5)(739 - x) = 857  

x + 1108.5 - 1.5x = 857  

- 0.5x = -251.5  

x = 503  

There were 503 $1 tickets sold.  

To find the number of $1.50 tickets, just plug this value of x into either one of the equations.  

(503) + y = 739       (739 - 503 = 236)

y = 236  

There were 236 $1.50 tickets sold.

3 0
4 years ago
Suppose that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water
Setler79 [48]

Answer:

Step-by-step explanation:

Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.

Let Q(t) be the quantity of salt at time t.

Q(0) = 70 pounds

Inflow of water = outflow = 4 gal/min

So resulting volume of tank at time t = 400 gallons

Rate of change of salt = inflow - outflow

= 0 - \frac{Q(t)}{400}

i.e. \frac{dQ}{dt} =\frac{-Q(t)}{400}

This is a variable separable equation

\frac{dQ}{Q}=-\frac{dt}{400} \\ln Q = {-\frac{t}{400}} +C\\Q = A e^{-\frac{t}{400}}

Use when t =0 Q = 70

A =70

So A(t) = Q(t) = 70 e^{-\frac{t}{400}} and

A(0) = Q(0) = 70 lbs.

7 0
3 years ago
Whats the a(y)? please help giving brainliest
Over [174]

It would mean A times Y.

4 0
3 years ago
If you flipped the graph of y=x^2+4x-4 vertically, you would get the graph of y=-x^2+4x-4
bazaltina [42]
True...............................................................
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