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2 years ago

13

xy=22 as a proportion please :) It would mean a lot if I could get a fast response! Please explain in detail because I don't get

what it is asking.

2 answers:

fgiga [73]2 years ago

7 0

Xy = 22
1 1

Cross multiply:
xy * 1 = 1 * 22

Simplifying
xy * 1 = 1 * 22

Reorder the terms for easier multiplication:
1xy = 1 * 22

Multiply 1 * 22
1xy = 22

Solving
1xy = 22

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '1y'.
x = 22y-1

Simplifying
x = 22y-1

Fiesta28 [93]2 years ago

3 0

The answer is 22
Have a nice day

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What is 111/6 and 4 1/3 as an improper fractions?

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Step-by-step explanation:

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3 years ago

Find the quotient using polynomial long division:

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(1) $50y^3=5y\cdot 10y^2$ , and

$10y^2\cdot(5y-4)=50y^3-40y^2$

Subtract this from $50y^3+10y^2-35y-7$ to get a remainder of

$(50y^3+10y^2-35y-7)-(50y^3-40y^2)=50y^2-35y-7$

What we've done here is show that

$\dfrac{50y^3+10y^2-35y-7}{5y-4}=10y^2+\dfrac{50y^2-35y-7}{5y-4}$

We can keep going as long as the degree of the remainder's numerator is at least the same as the degree of its denominator.

Next, $50y^2=5y\cdot 10y$ , and

$10y\cdot(5y-4)=50y^2-40y$

Subtract this from the previous remainder to get a new remainder of

$(50y^2-35y-7)-(50y^2-40y)=5y-7$

which means

$\dfrac{50y^3+10y^2-35y-7}{5y-4}=10y^2+10y+\dfrac{5y-7}{5y-4}$

Finally, $5y=5y\cdot1$ , and

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Subtract this from the previous remainder to get

$(5y-7)-(5y-4)=-3$

So we end up with

$\dfrac{50y^3+10y^2-35y-7}{5y-4}=\boxed{10y^2+10y+1}-\dfrac3{5y-4}$

(the quotient is the expression in the box)

(2) Using the same process as before:

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$\implies\dfrac{8m^4-4m^2+m+4}{2m+1}=4m^3-\dfrac{4m^3+4m^2+m+4}{2m+1}$

$-4m^3=2m\cdot(-2m^2)$

$-2m^2\cdot(2m+1)=-4m^3-2m^2$

$(-4m^3-4m^2+m+4)-(-4m^3-2m^2)=-2m^2+m+4$

$\implies\dfrac{8m^4-4m^2+m+4}{2m+1}=4m^3-2m^2-\dfrac{2m^2-m-4}{2m+1}$

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$(-2m^2+m+4)-(-2m^2-m)=2m+4$

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$1\cdot(2m+1)=2m+1$

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Answer:

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Step-by-step explanation:

Let P be the point.

As the point P is in the directed line segment from (-2,-8) to (5,-1) into the ratio of 1 to 6

i.e.

(x₁, y₁) = (-2,-8)

(x₂, y₂) = (5,-1)

Rise = y₂ - y₁ = -1 - (-8) = -1 + 8 = 7

Run = x₂ - x₁ = 5 - (-2) = 5 + 2 = 7

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Thus,

rise for P = 7 × 14% = 1

run for P = 7 × 14% = 1

Thus, coordinates of P will be:

x = -2 + 1 = -1

y = -8 + 1 = -7

Thus,

The coordinates of the point P in the directed line segment from (-2,-8) to (5,-1) that partitions the segment into the ratio of 1 to 6 will be:

(x, y) = (-1, -7)

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2 years ago

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3 years ago

Read 2 more answers