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noname [10]
3 years ago
15

Answer ASAP please !!

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0

Answer: rose = 7, shrub = 7

Step-by-step explanation:

First equation 10r + 4s = 98

r = (98-4s) / 10

Second equation 9r + 9s = 126

Substituting

9 (98-4s) / 10 + 9s = 126

9(49-2s) / 5 + 9s = 126

(441-18s) / 5 + 9s = 126

441 - 18s + 45s = 630

441+ 27s = 630

27s = 630 - 441

s = 189 / 27 = 7

Cost of shrub = 7

Cost of rose = (98 - 4s) / 10

= 98-28 = 70 / 10 = 7

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What is the quantity of 26/13
yan [13]

Answer:

the quantity is 2

Step-by-step explanation:

26/13=2

4 0
2 years ago
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Daniel kicks a soccer ball and the trajectory is modeled by f(t) =− 16t^2+ 32t .
vagabundo [1.1K]

Answer:

f(1) = 16

Domain: 0 ≤ t ≤ 2

Step-by-step explanation:

Given

f(t) = -16t²+ 32t

Solving (a): f(1)

Substitute 1 for t in f(t)

f(t) =− 16t²+ 32t .

f(1) =− 16 * (1)²+ 32 * 1

f(1) = -16 * 1 + 32

f(1) = -16 + 32

f(1) = 16

Solving (b): The domain

The implication of the given parameter in (b) is that t ≤ 2.

Since t represents time, t can't be negative.

Hence, a reasonable domain is

0 ≤ t ≤ 2

3 0
2 years ago
Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi
bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3}

In which L_{1}, L_{2} and L_{3} are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3}

In which E_{1},E_{2} and E_{3} are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

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So L_{1} = 0.30 and E_{1} = 0.18

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

5*0.075mg = 0.375mg of levonorgestrel and 5*0.040mg = 0.20mg of ethinyl estradiol are taken.

So L_{2} = 0.375 and E_{2} = 0.20

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

10*0.125mg = 1.25mg of levonorgestrel and 10*0.030mg = 0.30mg of ethinyl estradiol are taken.

So L_{3} = 1.25 and E_{3} = 0.30

The total milligrams of levonorgestrel is:

L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925

The total milligrams of ethinyl estradiol is:

E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0
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Answer:

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