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3 years ago

45 %of population of a town is female . what's the population of male if total population is 54320

Mathematics

2 answers:

Harman [31]3 years ago

5 0

Answer:29876

Step-by-step explanation:

Entire population is 100%

Male is 100%-45%

55%x54320=29876

Lubov Fominskaja [6]3 years ago

3 0

Answer:

29,876 males

Step-by-step explanation:

If 45% of 54320 population is female. The population of male is calculated below.

The total population is 100% and female is 45%. Thus: 100% - 45% = 55%.

Percentage of male population is 55%. Hence, 55% of 54320 is calculated thus:

$\frac{55}{100} \times 54320$

$= 0.55 \times 54320$

$= 29876$

Therefore, population of male if total population is 54320 is 29,876.

Check,

Female population percentage + male population percentage:

45% + 55% = 100%

24,444 + 29,876 = 54,320

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Answer:

The df values for the A x B interaction are also 3,40

Step-by-step explanation:

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3 years ago

Find the first four nonzero terms in a power series expansion about xequals0 for the solution to the given initial value problem

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Answer:

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Step-by-step Explanation:

This is the interpretation of the question

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3 years ago

Bill is bisecting an angle with technology Which of the following describes his next step?

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Answer:

Mark point E where the circle intersects segment BC

Step-by-step explanation:

Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.

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Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

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n = sample of containers = 15

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The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

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