Lisa wrote the following statement:

Please help. Write the first four terms of the sequence. f(n) = (n-1) (n-2)

Hoochie [10]

F(1)=(0)(-1)=0
f(2)=(1)(0)=0
f(3)=(2)(1)=2
f(4)=(3)(2)=6

6 0

4 years ago

Determine if a triangle with side lengths 8, 14, and 15 is acute, right, or obtuse

asambeis [7]

Answer:

Acute

Step-by-step explanation:

The Converse of the Pythagorean Theorem states that:

If $a^2+b^2 > c^2$ then the triangle is acute.
If $a^2+b^2 < c^2$ then the triangle is obtuse.
If $a^2+b^2 = c^2$ then the triangle is right.

The side lengths 8, 14, and 15 are given. We can assume the hypotenuse (or c) is the longest side length, so it is 15.

c = 15

It doesn't matter which order of the numbers are plugged in for a and b, so a and b will be 8 and 14.

a = 8
b = 14

Now we have to add $a^2$ and $b^2$ to see if the sum is greater than, less than, or equal to 15 (c).

$a^2 + b^2$
$8^2 + 14^2$

Calculate the rest of the problem.

$8^2=64 \newline 14^2=196$

$64+196=260$

We have to find what $15^2$ is before we can make a decision using the Converse of the Pythagorean Theorem.

$15^2=225$

260 ( $a^2+b^2$ ) is greater than 225 ( $c^2$ ). This means that the triangle is acute because $a^2+b^2>c^2$ .

6 0

3 years ago

PLZZZZZ HLPPPPP MEEEEEEEEEE NOW <3

DochEvi [55]

Answer:

$g(x) = x^{2} + 6\cdot x + 7$

Step-by-step explanation:

The blue parabola is only a translated version of the red parabola. The standard form of a vertical parabola centered at (h,k), that is, a parabola whose axis of symmetry is parallel to y-axis, is of the form:

$y - k = C\cdot (x-h)^{2}$

Where:

$h$ , $k$ - Horizontal and vertical components of the vertex with respect to origin, dimensionless.

$C$ - Vertex constant, dimensionless. (If C > 0, then vertex is an absolute minimum, but if C < 0, then vertex is an absolute maximum).

Since both parabolas have absolute minima and it is told that have the same shape, the vertex constant of the blue parabola is:

$C = 1$

After a quick glance, the location of the vertex of the blue parabola with respect to the origin is:

$V(x,y) = (-3,-2)$

The standard form of the blue parabola is $y+2 = (x+3)^{2}$ . Its expanded form is obtained after expanding the algebraic expression and clearing the independent variable (y):

$y + 2 = x^{2} +6\cdot x + 9$

$y = x^{2} + 6\cdot x + 7$

Then, the blue parabola is represented by the following equations:

$g(x) = x^{2} + 6\cdot x + 7$

8 0

4 years ago

Beth and Billy are biking to their friend Bernie's house. After 1 mile, Beth and Billy have traveled 4/5 of the total distance t

LenKa [72]

Answer: they need to cover 0.25 miles.

Step-by-step explanation:

Let x represent the total distance that they have to cover to get to Bernie's house.

Beth and Billy are biking to their friend Bernie's house and after 1 mile, Beth and Billy have traveled 4/5 of the total distance to Bernie's house. This would be expressed as

4.5 × x = 1

4x/5 = 1

Multiplying the left hand side and the right hand side of the equation by 5, it becomes

4x/5 × 5 = 1 × 5

4x = 5

Dividing the left hand side and the right hand side of the equation by 4, it becomes

4x/4 = 5/4

x = 1.25

Therefore, the remaining distance that they need to cover to arrive at Bernie's is

1.25 - 1 = 0.25 miles

3 0

3 years ago

6[5 x (41 - 36) - (8 + 14)]

Otrada [13]

Answer:

i want to say good bye my friend

the brainly is gonna delet this

5 0

3 years ago