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d1i1m1o1n [39]
3 years ago
9

X 10 Z 20 find x y and z

Mathematics
1 answer:
Reil [10]3 years ago
8 0

Answer:

y is 30

Step-by-step explanation:

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PLEASE ANSWER THIS FAST!!!!!!
o-na [289]

Answer:

B

Step-by-step explanation:

The correct answer is B

GK = 5 and KF = 5

5/5 = 1

HJ = 3

JG = 3

HJ/JG = 1

7 0
3 years ago
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astraxan [27]

Answer:

wrong

Step-by-step explanation:

5 0
3 years ago
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Chandler earns a base pay of $2,200 per month. He also earns a commission of 4% of his total sales . One month Chander earned $2
Kipish [7]
The answer is $333.33 hope it helps
8 0
3 years ago
A cold drink is poured out at 52°F. After 2 minutes of sitting in a 72°F room, its temperature has risen to 55°F. Find an equati
I am Lyosha [343]

Answer:

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

Step-by-step explanation:

For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.

We can model that in this way

\frac{dT}{dt}=k*(T_r-T)

If we rearrange and integrate

\int\frac{dT}{(T-Tr)} =-k*\int dt\\\\ln(T-T_r)=-kt+C1\\\\T-T_r=Ce^{-kt}\\\\T=T_r+Ce^{-kt}

We know that at time 0, the temperature of the drink was 52°F. Then we have:

T=T_r+Ce^{-kt}\\\\52=72+Ce^0=72+C\\\\C=-20

We also know that at t=2, T=55°F

T=T_r+Ce^{-kt}\\\\55=72-20e^{-k*2}\\\\e^{-k*2}=(72-55)/20=0.85\\\\-2k=ln(0.85)=-0.1625\\\\k=0.08

The model for the temperature of the drink can be written as

T=72-20e^{-0.08t}

7 0
4 years ago
Suppose that an individual has a body fat percentage of 13.7% and weighs 164 pounds. How many pounds of her weight is made up of
Vinvika [58]
164×13.7/100=22.47 kg
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