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2 years ago

6

Emily and Lily are reading the same copy of the same book for a summer reading assignment.

1 answer:

AnnyKZ [126]2 years ago

7 0

Answer:

Step-by-step explanation:

emily : 16 + 22x....with x being the number of days

Lily : 24 + 18x

16 + 22x = 24 + 18x

22x - 18x = 24 - 16

4x = 8

x = 8/4

x = 2 <==== they will be on the same page in 2 days

16 + 22x = 16 + 22(2) = 16 + 44 = 60

24 + 18x = 24 + 18(2) = 24 + 36 = 60

and they will both be on page 60 <===

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What is the answer to -1 = -5/2 (-2) + 4

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Answer:

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Step-by-step explanation:

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2 years ago

Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

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Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

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Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

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Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

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$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

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