A water molecule (H2O) is produced and released. both glucose and fructose is a monosaccharide, when 2 combined together, a disaccharide is formed. this process is called condensation, and it releases an extra water molecule because the water molecule is removed.
when those 2 splits up, it will use up that extra water molecule, and that process is called hydrolysis.
<span>Movement, Responsiveness, Digestion, Metabolism, Excretion, reproduction, Growth. List the Functional Characteristics necessary to maintain life in humans.<span>Movement. ... </span><span>Responsiveness. ... </span><span>Digestion. ... </span><span>Metabolism. ... </span><span>Excretion. ... </span><span>Reproduction. ... </span><span>Growth..</span></span>
Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.