Answer:
1. Yes
∆RST ~ ∆WSX
by SAS
2. Yes
∆ABC ~ ∆PQR
by SSS
3. Yes
∆STU ~ ∆JPM
by SAS
4. Yes
∆DJK ~ ∆PZR
by SAS
5. Yes
∆RTU ~ ∆STL
by SAS
5. Yes
∆JKL ~ ∆XYW
by SAS
6. No
7. Yes
∆BEF ~ ∆NML
by SAS
8. Yes
∆GHI ~ ∆QRS
by SSS
9. x=22
10. x=12
Step-by-step explanation:
1. RS/WS=ST/SX and m<RST=m<WSX
2. AB/PQ=8/6=4/3
BC/QR=AC/PR=12/9=4/3
AB/PQ=BC/QR=AC/PR
3. ST/JP=10/15=2/3
SU/JM=14/21=2/3
ST/JP=2/3=SU/JM
and m<TSU=70°=m<PJM
4. DK/PR=8/4=2
JK/ZR=18/9=2
DK/PR=2=JK/ZR
and m<DKJ=65°=m<PRZ
5. RT/ST=UT/LT
and m<RTU=m<STL
6. KL/YW=20/18=10/9
JL/XW=36/24=3/2
KL/YW=10/9≠3/2=JL/XW
7. BF/NL=24/16=3/2
BE/NM=39/26=3/2
BF/NL=3/2=BE/NM
and m<EBF=m<MNL
8. GH/QR=32/20=8/5
HI/RS=40/25=8/5
GI/QS=24/15=8/5
GH/QR=HI/RS=GI/QS=8/5
9. x/33=18/27
Simplifying the fraction on the right side of the equation:
x/33=2/3
Solving for x: Multiplying both sides of the equation by 33:
33(x/33)=33(2/3)
x=11(2)
x=22
10. x/16=9/12
Simplifying the fraction on the right side of the equation:
x/16=3/4
Solving for x: Multiplying both sides of the equation by 16:
16(x/16)=16(3/4)
x=4(3)
x=12
3x + 9 = 90
3x = 90 - 9 = 81
x = 81/3 = 27
x = 27
Answer:
Step-by-step explanation:
The monthly cost will be $17.14
Step-by-step explanation:
Given that the monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes) then this can be presented in a table form as;
<u>Time in minutes (x)</u> <u>Cost in dollars (y)</u>
50 $12.55
102 $ 17.23
Take the values as ordered pairs to represent coordinates for points that satisfy the linear function
(50,12.55) and (102,17.23)
Finding the slope of the graph using these points
slope,m=Δy/Δx
m=Δy=17.23-12.55 =4.68
Δx=102-50=52
m=4.68/52 =0.09
Finding the equation of the linear function using m=0.09, and point (50,12.55)
m=Δy/Δx
0.09=y-12.55/x-50
0.09(x-50)=y-12.55
0.09x-4.5=y-12.55
0.09x-4.5+12.55=y
y=0.09x+8.05
So for 101 minutes , the cost will be;
y=0.09*101 +8.05
y=9.09+8.05 = $17.14
Learn More
Linear functions : brainly.com/question/11052356
Keyword : linear function
#LearnwithBrainly
He can conclude that the system of equations has no solution since one equation in it always results with false equivalency.
Hope this helps.
r3t40
