Question

What is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? y − 5 = −3(x + 2) y − 5 = 3(x + 2) y − 11 = −3(x − 2) y − 11 = −3(x + 2)

Answer 1

Answer:

y - 11 = - 3(x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) is a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 2, 11)

m = $\frac{11-5}{-2-0}$ = $\frac{6}{-2}$ = - 3

Use either of the 2 given points for (a, b)

Using (a, b) = (- 2, 11), then

y - 11 = - 3(x - (- 2)), that is

y - 11 = - 3(x + 2)