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wlad13 [49]
3 years ago
12

In number theory, a perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the

sum of its positive divisors excluding the number itself (also known as its aliquot sum). Equivalently, a perfect number is a number that is half the sum of all of its positive divisors (including itself). Write a Python3 program to check if a user-entered number is a perfect number or not. Use exception handling to handle invalid inputs.
Computers and Technology
1 answer:
rusak2 [61]3 years ago
8 0

Answer:

Explanation:

def the_perfect(n):

  try: #exception handling if n is a negative number

       n > 0

   except: #return -1 if the error is reached

       return -1

  else:

        total = 0

        for i in range(1, n): #for loop from 1 to the target number

           if n % i == 0:

               total += i

   return total == n  #should return true if number is perfect number

print(perfect_number(8))

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Answer:

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Explanation:

An avoidance spiral is a spiral in which parties avoid the conflicts at all cost in which leads to reducing the influence, dependence, etc. This spiral can also be destructive.

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3 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

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       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

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       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

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       System.out.println(punc+" punctuations");

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   }

   

}

This is one example of how it could be done.

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