Question

On a standardized exam, the scores are normally distributed with a mean of 200 and a standard deviation of 10. Find the z-score of a person who scored 181 on the exam.

Answer 1

Answer:

$z=-1.9$

Step-by-step explanation:

We have been that on a standardized exam, the scores are normally distributed with a mean of 200 and a standard deviation of 10. We are asked to find the z-score of a person who scored 181 on the exam.

We will use z-score formula to solve our given problem.

$z=\frac{x-\mu}{\sigma}$, where,

z = z-score,

x = Random sample score,

$\mu$ = Mean,

$\sigma$ = Standard deviation.

Upon substituting our given values in above formula, we will get:

$z=\frac{181-200}{10}$

$z=\frac{-19}{10}$

$z=-1.9$

Therefore, the z-score of the person would be $-1.9$.