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serg [7]
4 years ago
7

Some Reactions are endothermic

Chemistry
1 answer:
Alinara [238K]4 years ago
8 0

Answer:

endothermic means energy is taken in and temperature increases.

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When would a cell use Active Transport? Mark all that apply.
Westkost [7]

Answer:

a c e

Explanation:

4 0
3 years ago
A 4.80g piece of magnesium (Mg) displaces 2.76mL of water when it is placed in a graduated cylinder. What is the density of magn
AnnZ [28]

Answer:

<h2>1.74 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{4.80}{2.76}  \\  = 1.73913...

We have the final answer as

<h3>1.74 g/mL</h3>

Hope this helps you

8 0
3 years ago
How many moles of CO2 are in 870 mL of a 0.75 M solution?
alukav5142 [94]
Volume in liters:

870 mL / 1000 => 0.87 L

Moles ( CO₂) =  molarity x volume

Moles (CO₂) = 0.75 x 0.87

= 0.6525 moles of CO₂

hope this helps!
8 0
3 years ago
Read 2 more answers
6. List the following particles in size order, from<br> biggest to smallest?
Arte-miy333 [17]

Answer:

the particles, molecules, and gas range from smallest to largest in the following order: electron < proton < atom <...

5 0
3 years ago
Suppose that you add 26.7 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the adde
nadya68 [22]

Answer: The molar mass of the unknown compound is 200 g/mol

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=2.74^0C = Depression in freezing point

i= vant hoff factor = 1 (for molecular compound)

K_f = freezing point constant = 5.12^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (benzene)= 0.250 kg  

Molar mass of solute = M g/mol

Mass of solute  = 26.7 g

2.74^0C=1\times 5.12\times \frac{26.7g}{Mg/mol\times 0.250kg}

M=200g/mol

Thus the molar mass of the unknown compound is 200 g/mol

4 0
4 years ago
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