The solutions of the equations for x are given as follows:
a. x = 36.
b. x = 15.
<h3>What is the solution for item a?</h3>
The equation for item a is given by:
x/3 - 5 = 7
Isolating x, we have that:
x/3 = 12
x = 3 x 12
x = 36.
<h3>What is the solution for item b?</h3>
The equation for item b is given by:
x/2 - 5 = 2.5
Isolating x, we have that:
x/2 = 7.5
x = 7.5 x 2
x = 15.
Hence the solutions are:
a. x = 36.
b. x = 15.
More can be learned about equations at brainly.com/question/25537936
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Answer:
2
Step-by-step explanation:
Given
See attachment for chart
Required
Number of off days
To do this, we simply calculate the expected value of the chart.
This is calculated as:
Where
x = days
f = chances
So, we have:
Let the slower cars speed equal X.
The faster cars speed would be X+5 ( 5 mph faster).
They traveled for 3 hours
Multiply the time of travel by speed to equal the number of miles traveled.
So you have:
3X + 3(X+5) = 267 miles
Simplify the left side:
3X + 3X+15 = 267
Combine like terms:
6x + 15 = 267
Subtract 15 from each side"
6x = 252
Divide each side by 6:
x = 252 / 6
X = 42
The slower car was traveling at 42 mph and the faster car was traveling at 47 mph.
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
Answer:
cm
Step-by-step explanation:
if using centimeters to determine the perimeter then it's just cm.
If you're using centimeters to determine area it would be cm^2.
If you're using centimeters to determine volume it would be cm^3.
I hope this helps you. Have a blessed day.
:);)
