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3 years ago

Use the function r=n-7 to find the value of r when n =10

Mathematics

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

r=3

Step-by-step explanation:

if n=10

r=n-7

r=(10)-7

r=3

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Amy had $28 dollar’s to spend on school supplies. After buying 7 pens, she had $20.30 left. How much did each pen cost including

Airida [17]

Answer:

Step-by-step explanation:

If Amy started with 28 dollars and bought 7 pens, then had 20.30 dollars, we can subtract to find the price of all 7 pens.

28-20.30=7.70 dollars

now to find the amount for EACH pen, we divide by 7

7.70/7=1.1

each pen costed Amy 1 dollar and 10 cents with tax

5 0

3 years ago

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?????????????? anyone

Keith_Richards [23]

Answer:

(6 + 3/n) -8

Step-by-step explanation:

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2 years ago

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Variation table of this g(x)=2x^3 -x^2 -4x +6

Mrac [35]

Answer:

$2x^{3} - x^{2} - 4x +6$

2x-x-4 $x^{3-2}$ + 6

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7 0

2 years ago

Y=3x-1 substitute -3 for x

Brums [2.3K]

The answer should be -10

5 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago

Use the function r=n-7 to find the value of r when n =10​

Use the function r=n-7 to find the value of r when n =10