Distribute the five to [3q-10]
Combine like terms [15q] and [-5q]
Add 50 on each side
Divide by 10 on each side
Simplify
Using the identity cos^2(A)=1-sin^2(A)
transform
integral of sin^2(πx)cos<span>^5(πx)dx
=</span>integral of sin^2(πx)[1-sin^2(πx)]^2 cos(πx)dx
=integral of [sin^2(πx)-2sin^4(πx)+sin^6(πx)]cos(πx)dx
using the substitution u=sin(πx), du=πcos(πx)dx
=integral of [u^2-2u^4+u^6] (du/π)
=1/π[u^3/3-(2/5)u^5+u^7/7] + C
back substitute u=sin(πx)
=1/π[sin(πx)^3/3-(2/5)sin(πx)^5+sin(πx)^7/7]
or
=sin(πx)^3/3π-2sin(πx)^5/5π+sin(πx)^7/7π
Answer:
Divide 11 by 10 . Place this digit in the quotient on top of the division symbol. Multiply the newest quotient digit (1) by the divisor 10 . Subtract 10 from 11 . :) Hope this helps!
Answer:
90
Step-by-step explanation:
first, divide 27 by 6 to get 4.5, then multiply by 20