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daser333 [38]
2 years ago
11

Help!!!!!!!!!! TYSM if you answer this!!!!!!!!!!!

Mathematics
1 answer:
Arlecino [84]2 years ago
8 0

Answer:

10p+5

Step-by-step explanation:

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I HAVE TO ADD SMTH HERE
mel-nik [20]

Answer:

-7

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
stellarik [79]

Answer:

a) There is a 59.87% probability that none of the LED light bulbs are defective.

b) There is a 31.51% probability that exactly one of the light bulbs is defective.

c) There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) There is a 100% probability that three or more of the LED light bulbs are not defective.

Step-by-step explanation:

For each light bulb, there are only two possible outcomes. Either it fails, or it does not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 10, p = 0.05

a) None of the LED light bulbs are defective?

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}*(0.05)^{0}*(0.95)^{10} = 0.5987

There is a 59.87% probability that none of the LED light bulbs are defective.

b) Exactly one of the LED light bulbs is defective?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}*(0.05)^{1}*(0.95)^{9} = 0.3151

There is a 31.51% probability that exactly one of the light bulbs is defective.

c) Two or fewer of the LED light bulbs are defective?

This is

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = 2) = C_{10,2}*(0.05)^{2}*(0.95)^{8} = 0.0746

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.5987 + 0.3151 + 0.0746 0.9884

There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) Three or more of the LED light bulbs are not defective?

Now we use p = 0.95.

Either two or fewer are not defective, or three or more are not defective. The sum of these probabilities is decimal 1.

So

P(X \leq 2) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = 0) = C_{10,0}*(0.95)^{0}*(0.05)^{10}\cong 0

P(X = 1) = C_{10,1}*(0.95)^{1}*(0.05)^{9} \cong 0

P(X = 2) = C_{10,1}*(0.95)^{2}*(0.05)^{8} \cong 0

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0

P(X \geq 3) = 1 - P(X \leq 2) = 1

There is a 100% probability that three or more of the LED light bulbs are not defective.

8 0
3 years ago
Which equation shows the distributive property? (a) 6 x 3 + 6 x 8 = 6 x (3 + 8) (b) 5 + (22 + 19) = (5 + 22) + 19 (c) 20 x 10 =
dimulka [17.4K]
The correct answer is A
8 0
2 years ago
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On an architect's drawing of a house, 1 inch represents 7 feet. If the bedroom window is 5 inches long on the drawing, how long
Pavel [41]
We can use ratios here. The real size would have to be proportional, meaning that if I increase the line on the drawing 5 times, the real size would have to increase 5 times as well.

We can obviously see, after having said that, that the real window would have to be 35ft long (because we multiplied 1 inch by 5, and if 1 inch represents 7 feet, then we also have to multiply that by 5 so it’s proportional, and 7*5=35)

We can check too — 1 in : 7 ft = 5 in : x ft

x = (7ft * 5in) / 1in — we would get the same result :)
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2 years ago
The annual inflation rate is 3.5% per year. If a movie costs $7.50, determine which of the following graphs best models the chan
madam [21]
The price of movie after a year would be
7.50+\frac{3.5}{100} *7.50 = 7.7625$
8 0
3 years ago
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