For this case we have the following functions:
![f (x) = 3x-1\\g (x) = x + 2](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%203x-1%5C%5Cg%20%28x%29%20%3D%20x%20%2B%202)
We must find
. By definition we have to:
![(f + g) (x) = f (x) + g (x)](https://tex.z-dn.net/?f=%28f%20%2B%20g%29%20%28x%29%20%3D%20f%20%28x%29%20%2B%20g%20%28x%29)
So:
![(f + g) (x) = 3x-1 + (x + 2)\\(f + g) (x) = 3x-1 + x + 2](https://tex.z-dn.net/?f=%28f%20%2B%20g%29%20%28x%29%20%3D%203x-1%20%2B%20%28x%20%2B%202%29%5C%5C%28f%20%2B%20g%29%20%28x%29%20%3D%203x-1%20%2B%20x%20%2B%202)
We add similar terms:
![(f + g) (x) = 4x + 1](https://tex.z-dn.net/?f=%28f%20%2B%20g%29%20%28x%29%20%3D%204x%20%2B%201)
Answer:
![(f + g) (x) = 4x + 1](https://tex.z-dn.net/?f=%28f%20%2B%20g%29%20%28x%29%20%3D%204x%20%2B%201)
Option D
Answer:
Here is the answer
Step-by-step explanation:
Answer:
$3.33
Step-by-step explanation:
Divide 20 by 6
Answer:
It's gonna be C and good luck!
Inequality symbols need to be reversed when multiplying or dividing by a negative number, because that reverses the ordering of values.
2 > 1
-2 < -1 . . . . . multiplied or divided by -1
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A more "interesting" case is when a function is applied that has a negative slope.
0 < a < b < π
cos(0) > cos(a) > cos(b) > cos(π)