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3 years ago

Please help if you can!

Mathematics

1 answer:

Yuliya22 [10]3 years ago

3 0

Answer:

y = (2/3)x + 3

Step-by-step explanation:

Notice that if we start at any x value shown in the table and increase x by 3, y will increase by 2. Thus, the slope of the line is 2/3.

From the entry (0, 3), we know that the y-intercept is b = 3.

Thus, y = mx + b becomes:

y = (2/3)x + 3

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Use the identity (x+y)(x2−xy+y2)=x3+y3 to find the sum of two numbers if the product of the numbers is 10, the sum of the square

professor190 [17]

Answer:

The sum of two numbers is 7.

Step-by-step explanation:

Given : the product of the numbers is 10, the sum of the squares of the numbers is 29, and the sum of the cubes of the numbers is 133.

Using identity $(x+y)(x^2-xy+y^2)=x^3+y^3$ and given details, we have to find the sum of two numbers.

Since, given that the product of the numbers is 10 that is $xy=10$

Also, given the sum of the squares of the numbers is 29 that is $x^2+y^2=29$

and the sum of the cubes of the numbers is 133 that is $x^3+y^3=133$

Using, the given identity $(x+y)(x^2-xy+y^2)=x^3+y^3$ ,

Substitute, the given values, we have,

$(x+y)(29-10)=133$

Simplify , we get,

$(x+y)(19)=133$

Divide both side by 19, we have,

$(x+y)=7$

Thus, the sum of two numbers is 7.

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