Yes, it is okay. you should never change your hypothesis if it was wrong.
Answer:
q = 0.42
Explanation:
This question is an example of Hardy-Weinberg question and there are two equations necessary to carry out this question;
p + q = 1
p² + 2pq + q² = 1
where;
p = the frequency of the dominant allele
q = the frequency of the recessive allele
p² = the frequency of individuals with homozygous dominant genotype
2pq = the frequency of individuals with heterozygous genotype
q² = frequency of individuals with the homozygous recessive genotype
Since the total population = 425
q² = 
= 
q² = 0.1765
To find q; we need to square root both side to eliminate the square from q².
∴
q = 0.4201
q = 0.42 (to two decimal places)
Answer: what the girl said above what right
If two Bb guinea pigs cross, there are four possible outcomes:
- both pass the B: the son is BB
- one of the pass the B and the other pass the b: the son is Bb
- both pass the b: the son is bb
Since B (being black) is dominant, the son will be black in both BB and Bb cases. In order for a son to be brown, he must be a pure bb specimen.
So, if all of the offspring are black, it means that all four guinea pigs are either BB or Bb, which in turn means that at least one of the parents passed the B gene.