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Tju [1.3M]
3 years ago
9

Hillside Garden Co. uses the aging of accounts receivable method to determine its allowance for uncollectible accounts. On Janua

ry 16, Hillside Garden Co. wrote off an uncollectible account in the amount of $1,300. What effect does the write off have on the company’s financial statements
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

The answer is: The write off will reduce the Accounts Receivables account in the balance sheet by $1,300.

Step-by-step explanation:

When you use the aging method for determining uncollectible accounts, this will affect the balance sheet.

The January 16 records should be:

  • Dr Allowance for Doubtful Accounts 1,300
  • Cr Accounts Receivables 1,300

The write off will reduce the Accounts Receivables account in the balance sheet by $1,300. The Allowance for Doubtful Accounts account is a contra asset account that reduces the value of assets in the balance sheet.

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Use linear regression to find a
Inessa [10]

A function that fits the following points (0,5), (2,-13) is y = 9x + 5

<h3>Equation of a line</h3>

The equation of a line in slope-intercept form is expressed as;

y =mx +b

where;

m is the slope

b is the intercept

Given the following coordinates (0,5), (2,-13)

Slope = -13-5/2-0
Slope = -18/-2

Slope = 9

Since the y-intercept is b = 5, hence the equation of the line will be y = 9x + 5

Learn more on linear regression here; brainly.com/question/25987747

#SPJ1

6 0
2 years ago
Suppose f (x) = x^2. Find the graph of f(x+2)
NISA [10]
\bf ~~~~~~~~~~~~\textit{function transformations}&#10;\\\\\\&#10;% templates&#10;f(x)={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;~~~~y={{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)={{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\\\&#10;f(x)={{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\\\\&#10;--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;~~~~~~\textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;~~~~~~if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;~~~~~~if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;~~~~~~if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind,

\bf f(x)=x^2\qquad \quad f(x+2)=(x+2)^2\implies f(x+2)=\stackrel{A}{1}(\stackrel{B}{1}x\stackrel{C}{+2})^2\stackrel{D}{+0}

C = 2         B = 1        C/B = 2/1 or +2,    horizontal left shift of 2 units

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8 0
3 years ago
HELP! SIMPLIFY!
Vitek1552 [10]
1)  (m³n⁵)(mn⁴)
     -----------------
      m⁻³n²

Simplify.

m⁴n⁹
-------
m⁻³n²

When the bottom power is a negative, you add it to the power on top, & when the power is a positive, you subtract it.

m⁴ + m³ = m⁷

n⁹ - n² = n⁷

So, our answer for #1 is m⁷n⁷

2)  6a²b³
     ---------
        4a

Please read rules in #1.

6 / 4 = 3/2 & a² - a = a

So, our answer is 3a
                               -----
                                 2

3)  5⁶a⁶b³
     ---------
       5²ab³
5⁶ - 5² = 5⁴ AND a⁶ - a = a⁵ AND b³-b³ = 0

So, our answer is 5⁴a⁵

Simplify 5⁴

5 × 5 × 5 × 5 = 625

So, our final answer is :

625a⁵

~Hope I helped!~
6 0
3 years ago
suppose tortilla chips cost 24.5 cents per ounce. what would a bag of chips cost if it contained 20 oz? Round your answer to the
Ierofanga [76]

Answer:

Step-by-step explanation:

So this is multiplication

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6 0
2 years ago
Twoooooooooooooooooooooooooooo
KatRina [158]

Answer:

n = 60.22

Step-by-step explanation:

Hello

To find Sn, we need to draw out equations for each a₇ and a₁₉

In an arithmetic progression,

Sn = a + (n-1)d

Where Sn = sum of the A.P

a = first term

d = common difference

a₇ = 32

32 = a + (7-1)d

32 = a + 6d ........equation (i)

a₁₉ = 140

140 = a + (19-1)d

140 = a + 18d .........equation (ii)

Solve equation (i) and (ii) simultaneously

From equation (i)

32 = a + 6d

Make a the subject of formula

a = 32 - 6d .....equation (iii)

Put equation (iii) into equation (ii)

140 = (32 - 6d) + 18d

140 = 32 - 6d + 18d

Collect like terms

140 - 32 = 12d

12d = 108

d = 108 / 12

d = 9

Put d = 9 in equation (i)

32 = a + 6(9)

32 = a + 54

a = 32 - 54

a = -22

When Sn = 511

Sn = a + (n - 1)d

Substitute and solve for n

511 = -22 + (n-1) × 9

511 = -22 + 9n - 9

511 = -31 + 9n

511 + 31 = 9n

542 = 9n

n = 542 / 9

n = 60.22

5 0
3 years ago
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