Answer:
34
Step-by-step explanation:
I think the answer is 59.29,24.2×245%=24.2
Answer:
f = 0
x > 2y
x ≤ 8
S ≥ 18
Step-by-step explanation:
Let 'f' represent the number of free throws.
Let 'x' represent the number of 2 - point baskets.
Let 'y' represent the number of 3 - point baskets.
Let S represent the Season high.
1) Ryan says he did not shoot any free throws.
⇒ f = 0
2) 2 - point baskets more than twice the number of 3 - point baskets.
⇒ x > 2y
3) Number of two points is less than or equal to 8.
⇒ x ≤ 8.
4) Last Season high, he had scored 18 points. Note that the problem says, Ryan equaled or bettered than last season high. That means he should got at least 18 points this season. So, the equation would be:
S ≥ 18
Hello there! We are given the following equation and want to simplify it:

First, let's use the Distributive Property:
For this step, we are going to let:
After applying this version of the Distributive Property, we are given the equation:

We're going to use the distributive party again, but a slightly different version that's almost the same as first:
Using this on both terms of the equation changes the equation to:

Now, we just remove the parenthesis and combine like terms

This should be your answer. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
Option a.

Step-by-step explanation:
You have the following limit:

The method of direct substitution consists of substituting the value of
in the function and simplifying the expression obtained.
We then use this method to solve the limit by doing 
Therefore:


By definition, any number raised to exponent 0 is equal to 1
So


Finally
