Given/equations formed from text:
I: l=w+3
II: A=l*w
III: new area B=(l-2)*w
IV: B=A-30
substitute l in II with I to remove l:
II': A=l*w=
(w+3)*w=
w^2+3w
substitute l in III with I to remove l:
III': B=(l-2)*w=
(w+3-2)*w=
(w+1)*w=
w^2+w
substitute A and B from II' and III' into IV:
B=A-30
w^2+w=w^2+3w-30
30=2w
w=15
insert w=15 into I:
l=15+3=18
->
A) dimensions of full size rectangle are width 15 and length 18
dimensions of reduced size rectangle are width 15 and length 16
B) full size: 15*18=10*18+5*18=180+90=270cm^2
reduced size: 15*16=10*16+5*16=160+80=240cm^2
Y = mx + b
slope = m = 1/21, so we have
y = 1/2 x + b
The line passes through (2, 5), so we get
5 = 1/2 * 2 + b
5 = 1 + b
b = 4
The equation of the line is
y = 1/2 x + 4
Point (x, 3) has a y-coordinate of 3. We are looking for the x-coordinate.
y = 1/2 x + 4
3 = 1/2 x + 4
-1 = 1/2 x
x = -2
Answer:
10
Step-by-step explanation:
so do parentheses first so 12+8 is 20
1/2 of 20 is 10
Answer: 35/66 is your answer!
Step-by-step explanation:
