Select the correct answer.

Papa john is 50 years old. His age is 2 years more than 3 times the age of Jimmy John. How old is Jimmy?

mojhsa [17]

Answer:

<h2>Jimmy is 16 old.</h2>

Step-by-step explanation:

J - the age of Jimmy John

50 - the age of Papa John

3J + 2 - the age of Papa John

The euaqtion:

3J + 2 = 50 <em>subtract 2 from both sides</em>

3J + 2 - 2 = 50 - 2

3J = 48 <em>divide both sides by 3</em>

3J/3 = 48/3

J = 16

4 0

3 years ago

Need help not sure if my question is true or false

Alika [10]

The answer is false. The radius is half the diameter, not 2 times it.

7 0

3 years ago

An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i

Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = $\sqrt{(15-x)^2+1^2}$

The total time, 't', is given as follows;

$t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}$

The minimum value of 't' is found by differentiating with an online tool, as follows;

$\dfrac{dt}{dx} = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} = \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }$

At the maximum/minimum point, we have;

$\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0$

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

$t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89$

Therefore, the distance to run, x ≈ 14.96 mile

6 0

2 years ago

A patient is instructed to take three 50-mcg tablets of pergolide mesylate (Permax) daily. How many milligrams of the drug would

Black_prince [1.1K]

Answer:

The patient would receive 1.05mg of the drug weekly.

Step-by-step explanation:

First step: How many mcg of the drug would the patient receive daily?

The problem states that he takes three doses of 50-mcg a day. So

1 dose - 50mcg

3 doses - x mcg

x = 50*3

x = 150 mcg.

He takes 150mcg of the drug a day.

Second step: How many mcg of the drug would the patient receive weekly?

A week has 7 days. He takes 150mcg of the drug a day. So:

1 day - 150mcg

7 days - x mcg

x = 150*7

x = 1050mcg

He takes 1050mcg of the drug a week.

Final step: Conversion of 1050 mcg to mg

Each mg has 1000 mcg. How many mg are there in 1050 mcg? So

1mg - 1000 mcg

xmg - 1050mcg

1000x = 1050

$x = \frac{1050}{1000}$

x = 1.05mg

The patient would receive 1.05mg of the drug weekly.

6 0

3 years ago

In the year 2003, a company made $6.8 million in profit. For each consecutive year after that, their profit increased by 13%. Ho

LenKa [72]

Answer:

$7.7 million

Step-by-step explanation:

Given: $6.8 million profit made by company.

13% increase in profit every year.

Now, finding the company´s profit in the year of 2006.

As we know there is 13% increase in profit.

∴ Profit increase= $\frac{13}{100} \times 6.8= \$ 0.884$

Next adding company´s profit with increase in profit to get profit in the year 2006.

∴ $6.8+0.884= \$ 7.684$ ≅ $7.7

The company´s profit in the year 2006 is $7.7 million.

6 0

2 years ago