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Anarel [89]
3 years ago
10

Oshua's mother has a family Christmas gathering at 2:00. Joshua must travel 348 miles to join the festivities. He left his house

at 8:00 in the morning in order to arrive on time. What speed was Joshua driving?
Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

58 miles/hour

Step-by-step explanation:

Given that the family Christmas gathering has been scheduled at 2:00 p.m.,

and Joshua left the house at 8:00 a.m.

So, the total time available in order to arrive on time to attend the Christmas gathering, t=6 hours

The total distance, Joshua has to travel, d= 348 miles.

As average speed= (total distance)/(total time)

So, the average speed of driving = 348/6=58 miles/hour

Hence, Joshua must drive at an average speed of 58 miles/hour in order to arrive on time.

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Answer:

Angle RNQ is equal in measure to arc PR.

Step-by-step explanation:

Consider the complete question is,

Points N, P, and R all lie on circle O. Arc PR measures 120° How does the measure of angle RNQ relate to the measure of arc PR?

A.Angle RNQ is equal in measure to arc PR.

B.Angle RNQ is half the measure of arc PR.

C.Angle RNQ is twice the measure of arc PR.

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By the below attached diagram,

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m∠RNO = 60°,

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⇒  m∠RNQ = 180° - 60° = 120°,

But, Arc PR measures 120°

Hence, Angle RNQ is equal in measure to arc PR.

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