If you're behind like I am and are just now doing these assignments then good luck on catching up.
If it's AQRB Unit 2 Lesson 3 then the answers to the multiple choice are below, you'll need to do the essay and calculation on your own.
1: $674.64
2: $26, 255.38
3: $191, 398.49
4: $23, 884.84
each trial is independent so do
.5 x .5 x .5 or .5^3
.125 is the probability.
The answer is 2 = p
Explanation: Here the goal is to get the variable "p" by itself, so first your have to distribute 2 to (p-12) which gives you -10p = 2p-24. Then you add 10p on both sides so that the variable is on one side. Then you add 24 to both sides. After that you divide 12 from both sides, giving you 2 = P
-10P = 2(p-12)
-10p = 2p-24
+10p +10p
0 = 12p-24
+24 +24
24 = 12p
24÷12 = 12p÷12
2 = p
We see that they are made up of identical squares, meaning that each side of each square is the same length. There are 12 square sides that make up the perimeter of A, so we can do 72/12 which is 6. We see there are ten total square lengths on the perimeter of b, so we can do 6 times 10 which is 60 cm. That’s your perimeter.
Alright.
For 7, you'll want to put congruent sides equal to each other, assuming they are parallelograms. So, you'll get the two equations:
3x+2=23
2y-7=9
Solve using GEMDAS/PEMDAS, and you'll get these answers.
3x+2=23
3x=21
x=7
2y-7=9
2y=2
y=1
For 8, you'll want to do the exact same thing, formatting the numbers to equal each other. You'll get these two equations:
3y+5=14
2x-5=17
Solving them would make:
3y+5=14
3y=9
y=3
2x-5=17
2x=22
x=11
For 9, you have to remember that the angle opposite of one angle in a defined parallelogram are congruent. Thus:
130=2h
5k=50
solve them and you get
h=65
k=10
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Hope that helped. Good luck.
