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Dmitrij [34]
2 years ago
15

If the line above is translated 5 units up and 8 units left, what is the slope of thenew line?​

Mathematics
1 answer:
vazorg [7]2 years ago
3 0
The slope is 5/-8

Since rise/run...

Rise = +5 and Run = -8
You might be interested in
A boogie board that has a regular price of $6. If the sales tax on the boogie board is 7%, what is the total cost of the board?
zavuch27 [327]

Answer:

6.42$

Step-by-step explanation:

6.00 divided by 100 equals 0.6 multiplied by 7 equals 0.42 so the sales tax is 0.42 cents and the total is 6.42$

7 0
3 years ago
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
3 years ago
Can anyone explain me the steps I have to do to get my answer ?
ser-zykov [4K]
3.4% in decimal form is .034 = r
2014 - 2004 = 10 years = t

A = 45,000(1+.034)^10
A= 62,866
5 0
2 years ago
Read 2 more answers
Pls help is due tomorrow and if u help i will give u brainliest
Reil [10]

Answer:

Search it up

Step-by-step equation:

Just search up the website at the bottom of the paper.

6 0
3 years ago
What is 3 and 1/5 as a decimal
Musya8 [376]

Answer:

3.2

Step-by-step explanation:

1/5=0.2

3 + 0.2 = 3.2

6 0
3 years ago
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