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3 years ago

Is -0.232746284627 a rational or irrational

Mathematics

2 answers:

frosja888 [35]3 years ago

8 0

Rational because it keeps on going on and on

vovikov84 [41]3 years ago

6 0

Answer:

irrational

Step-by-step explanation:

that is..... if it keeps in continuing forever

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5/4 inches to 2/3 inch as a fraction in simplest form

never [62]

Answer:

6/4

Step-by-step explanation:

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3 years ago

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Let F (x; y) = xy2i + x2y j. Evaluate ∫F.ds (from c to [infinity]) where C is the upper half of the circle of radius 1 centered

77julia77 [94]

Answer:

The integral $\int F \bullets ds$ is 0.

Step-by-step explanation:

A parameterization of curve C can be:

X (t) = cost 0 <= t <= pi

Y (t) = sint 0 <= t <= pi

r (t) = costi + sintj

r '(t) = -sinti + costj

$Fds = [-costsin^3t + sintcos^3t] dt$

The integral $\int F \bullets ds$ is given by:

$\int _0^{\pi }\left[-costsin^3t + sintcos^3t dt\right]dt$

$= \int _0^{\pi }-sin ^3tcostdt + \int _0^{\pi }sintcos^3tdt = 0$

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3 years ago

Someone plz help me here ;-; it’s due today! I have another due today plz help I have to redo this one cause I got one wrong ;-;

Alja [10]

Answer:

I think It is D

7 0

3 years ago

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At the city museumy child admission is and admission is $9.30. On Monday four times as many adult tickets as child tickets were

Scilla [17]

Question:

At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?

Answer:

36 child tickets were sold

Solution:

Given that,

Cost of 1 child admission = $ 5.80

Cost of 1 adult admission = $ 9.30

Let "c" be the number of child tickets sold

Let "a" be the number of adult tickets sold

On Monday, four times as many adult tickets as child tickets were sold

Number of adult tickets sold = four times the number of child tickets

Number of adult tickets sold = 4(number of child tickets sold)

a = 4c ----- eq 1

They were sold for a total sales of $ 1548.00

number of child tickets sold x Cost of 1 child admission + number of adult tickets sold x Cost of 1 adult admission = 1548.00

$c \times 5.80 + a \times 9.30 = 1548$

5.8c + 9.3a = 1548 ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

Substitute eqn 1 in eqn 2

5.8c + 9.3(4c) = 1548

5.8c + 37.2c = 1548

43c = 1548

c = 36

Thus 36 child tickets were sold that day

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Answer:

Lo siento, no puedo ayudarte, porque esta resonancia es porque no tienes una imagen ni nada para que yo te ayude, lo siento, espero que tengas un buen día.

Step-by-step explanation:

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3 years ago