Answer:
Step-by-step explanation:
You move right 1 unit and left 6 units. You end at (0, 10). Where did you start?
2 answers:
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Answer:
The 't' test statistic = 1.46 < 1.69
The test of hypothesis is H 0 :μ = 800 is accepted
A sample of 30 bulbs are found came from average µ= 800
Step-by-step explanation:
Step 1:-
Given population of mean μ = 800
given size of small sample n =30
sample standard deviation 'S' = 45
Mean value of the sample χ = 788
Null hypothesis µ =800
alternative hypothesis µ ≠ 800
<u>Step 2</u>:-
The 't' test statistic t =
t = = 1.4607
<u>Step 3</u>:-
The degrees of freedom γ = n-1 = 30-1 =29
From "t" value from table at 0.05 level of significance ( t = 1.69)
The calculated value t = 1.4607 < 1.69
Therefore The null hypothesis H_{0} ' is accepted.
<u>conclusion</u>:-
A sample of 30 bulbs are came found from average µ= 800
First we find the zeroes so we don't take the integral of negative bits
4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4
![\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)= 10.6666666666](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E4_0%20%7B4x-x%5E2%7D%20%5C%2C%20dx%20%3D%5B2x%5E2-%20%5Cfrac%7B1%7D%7B3%7Dx%5E3%5D%5E4_0%3D%2832-%20%5Cfrac%7B64%7D%7B3%7D%29-%280%29%3D%20%2010.6666666666)
or aout 10 and 2/3
C is answer
4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4
C is answer