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Bas_tet [7]
3 years ago
8

COME GET SOME COINS >:)

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
8 0

Answer:

yes please

Step-by-step explanation:

forsale [732]3 years ago
4 0

Answer:

ok lol

Step-by-step explanation:

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How many variable terms are in the expression 3x to the third power Y plus 5X to the second power plus Y +9
andrew-mc [135]

Well, variables are stuff like x and y because they can represent a number. They are variable in an equation. so if you have (3x^3)+(5X^2)+Y+9 then your variables are x X and Y (im assuming the capital X is there and not a typo) if that was a typo and meant to be lowercase, then its just a 2 variable with the x and y

8 0
3 years ago
Kona wants to bake 30 loaves of bananas bread and nut bread one is 2.50 and other is 2.75 she wants to make are lasts 44$ write
kykrilka [37]

Answer:$79.25

Step-by-step explanation:

6 0
2 years ago
I have five numbers, the mean is 6, and the mode is 7 what could these numbers be?
storchak [24]

Answer:

3, 5, 7, 7, 8

Step-by-step explanation:

3, 5, 7, 7, 8

the mean = (3+5+7+7+8)/5 = 30/5= 6

the mode = 7

4 0
3 years ago
a file that is 278 megabytes is being downloaded. If downloaded is 14.1% complete, how many megabytes been downloaded? To round
Gekata [30.6K]
14.1% of 278 is 39.2. So 39.2 megabytes have been downloaded.
4 0
3 years ago
Read 2 more answers
Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer.
sdas [7]
Radius, r = 3

The equation of a sphere entered at the origin in cartesian coordinates is

x^2 + y^2 + z^2 = r^2 

That in spherical coordinates is:

x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)

where you can make u = r cos(phi) to obtain the parametrical equations

x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u

where theta goes from 0 to 2π and u goes from -r to r.

In our case r = 3, so the parametrical equations are:

Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
6 0
3 years ago
Read 2 more answers
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