Ask question

Ask question

All categories

3 years ago

13

Big babies: The Center for Disease Control and Prevention reports that 25% of baby boys 6-8 months old in the United States weig

h more than 20 pounds. A sample of 16 babies is studied.
D- Would it be unusual if more than 8 of them weigh more than 20 pounds

1 answer:

Nuetrik [128]3 years ago

8 0

Answer:

Yes, it is unusual if more than 8 of 16 baby boys weigh more than 20 pounds

Step-by-step explanation:

Given: 25% of baby boys 6-8 months old in the United States weigh more than 20 pounds. A sample of 16 babies is studied.

To find: whether it is unusual that more than 8 baby boys weigh more than 20 pounds

Solution:

Number of babies in a sample = 16

According to report of the Center for Disease Control and Prevention, 25% of baby boys 6-8 months old in the United States weigh more than 20 pounds.

So, $\frac{25}{100}(16)=4$ baby boys weigh more than 20 pounds.

But in the question, it's given that more than 8 baby boys weigh more than 20 pounds.

So, yes, it is unusual.

You might be interested in

If f(x) = 3x5 + 4x3 + 3, then what is the remainder when f(x) is divided by<br> x - 3?

VikaD [51]

Answer:

840

Step-by-step explanation:

8 0

3 years ago

Sorry for the wait plz help !!!!!!!

harkovskaia [24]

Answer:

it should be 2 units

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max

siniylev [52]

Answer:

A) The maximum error in the calculated surface area: $25cm^2$

Relative error: $0.013$

B) The maximum error in the calculated volume: $162cm^2$

Relative error: $0.019$

Step-by-step explanation:

A) The formula for the surface area is:

$A=4\pi r^2$

The measured value is the circumference which is equal to:

$C=2\pi r$

then the radius is:

$r=\frac{C}{2\pi}$

Substituting in the formula of the surface:

$A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}$

Using the formula to calculate the error:

$dy=f'(x)dx$

Where $x$ is the variable measured and $y$ is a function of $x$ ( $y=f(x)$ ).

$dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC$

We have C=80cm and dC=0.5cm

$dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2$

The relative error is the maximum error divide by the total area. The total area is: $A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2$

$\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013$

B) The formula for the volume is:

$V=\frac{4}{3} \pi r^3$

Using $r=\frac{C}{2\pi}$

$V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}$

The maximum error is:

$dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2$

The calculated volume is:

$V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743$

The relative error is:

$\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019$

3 0

3 years ago

DO NOT SEND ME PDFS OR I WILL REPORT ANSWER CORRECTLY FOR BRAINLIEST

Temka [501]

Answer:

D is the answer

Step-by-step explanation:

Because everyone wants smart phones so just make them all smart phones lol

8 0

3 years ago

Read 2 more answers

What expression is equivalent to 10(2p+q)

boyakko [2]

There aren't any answer options so I will just simplify the expression:
10(2p+q)
20p+10q

7 0

3 years ago