Here's the key:
Any radius that's perpendicular to a chord, bisects the chord.
So the piece of a radius that's perpendicular to the chord bisects it,
and the part of the chord that forms a side of the triangle is also 6.5 .
The triangle is a right triangle, and its hypotenuse is a radius of the circle.
the diameter of the circle is 16, so the length of the radius is 8 .
So now you know the length of the hypotenuse and one leg of a right
triangle, and side 'x' is the other leg.
This is where Pythagoras comes in.
(hypotenuse)² = (one leg)² + (the other leg)²
(8)² = (6.5)² + x²
64 = 42.25 + x²
x² = 64 - 42.25
x² = √21.75
x = about 4.664... (looks like choice-A)
I dont know if you wanted the steps but:
x^2-4x-6=0
plug it into the equation:
![[tex] \frac{4\sqrt{40}}{2}](https://tex.z-dn.net/?f=%20%5Btex%5D%20%5Cfrac%7B4%5Csqrt%7B40%7D%7D%7B2%7D%20)
[/tex]
x^2-4/3x+1/3 x=1 , x= 1/3
2x^2-3x+1=0 x=1 , x=1/2
6x^2+12x=-5
add the 5 to both sides
6x²+12x+5=0 plug the problem into the equation
x=
x=[
x=
x=
x=
Answer:
B
Step-by-step explanation:
Because its didn't say European
