The solution is the point where the two lines intersect (are equal) so y=y and we can say:
6-x=-10-x upon adding x to both sides:
6=-10
This is never true so there is no solution to this system of equations. And for this to be true the two lines must be parallel and have different y-intercepts...
1q+2=-6q+3+8q+4
1q+2=2q+7
<span>-2q -2q
</span>-q+2=7
<span> -2 -2
</span>-q=<span>5
-1 -1
q=-5
</span>
Answer:1. X=2 y=4
2. X=2.5 y=3
3.x=0 y=-1
Step-by-step explanation:
1. 6x=12
x=2
replace
4+y=8
y=4
2.
8x=20
x=2.5
replace
5+3y=14
y=3
3.
-6y=6
y=-1
replace
x=0
Answer:
The answer is 2a^3\sqrt11a
Step-by-step explanation:
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
