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MariettaO [177]
4 years ago
11

Please give sure answers :) 30 pts

Physics
1 answer:
prohojiy [21]4 years ago
5 0

freq is inversely proportional to wavelength

require a medium

transfer energy

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A potential difference of 300 volts is applied to a 2.0-µf capacitor and an 8.0-µf capacitor connected in series. (a) What are t
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Answer:

a) Q1=Q2=480μC   V1=240V   V2=60V

b) Q1=96μC   Q2=384μC   V1=V2=48V

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Explanation:

Let C1 = 2μC  and  C2=8μC

For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:

C=\frac{1}{\frac{1}{C1} +\frac{1}{C2} } = 1.6\mu C

Q_{T} = V_{T}*C_{T} = 480\mu C

V1 = \frac{Q1}{C1}=240V

V2 = \frac{Q2}{C2}=60V

For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:

V1=V2   So,  \frac{Q1}{C1} = \frac{Q2}{C2}

Total charge is the same calculated for part (a), so:

\frac{Qt - Q2}{C1} = \frac{Q2}{C2}   Solving for Q2:

Q2 = 384μC    Q1 = 96μC.

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V1=V2=48V

For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C  V1=V2=0V

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