In mathematics, patterns are expressed as equations that will help us determine projections. When you're doing experiments, you describe the relationship between two parameters by an equation. You do this by using your results. However, when you have an equation, you can use this to determine the value of one parameter with any random number of the other parameter.
Answer:
C
Explanation:
- Let acceleration due to gravity @ massive planet be a = 30 m/s^2
- Let acceleration due to gravity @ earth be g = 30 m/s^2
Solution:
- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:
t = v / a
t = v / 30
- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:
t = v / g
t = v / 9.81
- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C
Answer:
V=120m/s
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X (2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve
for this problem you must divide the problem into two parts 1 and 2, when the rocket accelerates (1), and when the rocket decelerates (2).
Then you raise equations 3 and 1 in both parts.
finally you use algebraic methods to find the value of speed
I attach the complete procedure
The test tube will be subject to centripetal acceleration. This acceleration is given by the following formula
(accel.) = (tangential velocity)^2 / (radius)
The velocity of the probe at a distance of 10 cm from the center of the centrifuge, can be calculated using the circumference of the circle:
where omega denotes the angular velocity (radians per second). So, combining both:
The test tube is subjected to an acceleration of 18434 m/s^2!