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Vinil7 [7]
4 years ago
9

What organisms apart from algae would have needed to be present to remove carbon dioxide from the early atmosphere??

Physics
1 answer:
QveST [7]4 years ago
7 0
Plants in general I think. 
photosynthetic organisms.
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The weight of an object on a planet depends not only on its mass, but also on its distance from the planets center. Uranus has m
Ierofanga [76]
The further an object is from the centre of a planet, the lower it's gravitational force. Uranus had 14 times as much mass as earth, but it's also a lot bigger than earth. So assuming an object is on the surface of Uranus, it would be really far away from the centre of Uranus, therefore the gravitational force is less.

Hope this helps!
5 0
3 years ago
Read 2 more answers
This problem has been solved!
AleksAgata [21]

Answer:the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward.

Explanation:

When a ball is tossed vertically upwards, it reaches its maximum point. This maximum point is known as the maximum height of the ball. At this maximum height, its velocity is zero, its acceleration is directed downwards and the force of gravity acting in the ball is directed downwards towards the earth.

6 0
4 years ago
What happens to a bowl of hot soup when it is placed into a freezer where the air Temperature is below freezing. How does this a
Artyom0805 [142]
It does not it when put in the freezer it freezes the steam
8 0
3 years ago
A boy is listening to the radio. The loudspeaker plays a musical note by vibrating 256 rimes esch second. How many times does th
Svet_ta [14]

Answer:

 f_tympanum = 256 Hz.

Explanation:

The eardrum is the vibrating membrane of the human ear, it works by resonance, that is, an external stimulus (force) makes it vibrate, as the eardrum is extremely light it can vibrate at the same frequency of the incident sound.

Consequently if the incident vibration is f = 256 hz, the eardrum resonates at the same frequency

            f_tympanum = 256 Hz.

As a reference the response of the eardrum goes from f = 20 Hz f = 20000 Hz

6 0
4 years ago
Please do not round the numbers
slamgirl [31]

Answer:

1)   λ = 24.7 cm,  2) f = 13.88 Hz, 3)  L = 117.3 cm

Explanation:

1) This is a resonance process, that is, the wave going downwards will interfere with the wave going upwards.

This is a tube with one end closed and the other open, at the closed end there is a node and at the open end a belly, so the resonances are

       L = λ / 4

       λ = 4L                     1st harmonic

       λ = 4L / 3                third harmonic

       λ = 4L / 5                fifth harmonic

       λ = 4L / n ’              n’ odd number   n ’= (2n +1)

the wavelength is requested for the eighth resonance n = 8, the corresponding prime number is

          n ’= 2 8 +1

          n ’= 17

we substitute

     λ = 4 105/17

     λ = 24.7 cm

2) the speed of the wave is related to the wavelength and frequency

          v =   λf

          f = v /λ

          f = 343 / 24.7

          f = 13.88 Hz

3) the next resonance occurs for n = 9, so the prime number is

         n ’= 2 9 +1

         n ’= 19

         L = n’ λ / 4

       

         L = 19 λ / 4  

We must suppose a value for the wavelength, if the wavelength is present in the tube and the length of the column increases, the resonance number increases

         L = 19 24.7/4

         L = 117.3 cm

8 0
3 years ago
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