Answer:
<em>The object with the twice the area of the other object, will have the larger drag coefficient.</em>
<em></em>
Explanation:
The equation for drag force is given as
where 
IS the drag force on the object
p = density of the fluid through which the object moves
u = relative velocity of the object through the fluid
p = density of the fluid
= coefficient of drag
A = area of the object
Note that is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid
The above equation can also be broken down as
∝ 
A
where is the pressure exerted by the fluid on the area A
Also note that = 
which also clarifies that the drag force is approximately proportional to the abject's area.
<em>In this case, the object with the twice the area of the other object, will have the larger drag coefficient.</em>
T=((2*1.8)/10)^(1/2)
t=.6sec
v=vintial+at
v=0-10 m/s^2(.6s)
v=-6m/s
Answer: 12 N to the right
Explanation:
If we calculate the net force acting on the box, we will have:
<u>In y-component:</u>
(1)
Where 
is the Normal force, directed upwards and 
is the weight of the box (gravity force), directed downwards.
(2)
(3) Hence the net force in the vertical component is zero
<u>In x-component:</u>
(4)
Where 
and 
(5)
(6) This is the net force in the horizontal component
Therefore, the total net force acting on the box is 12 N directed to the right
<span>When you bring a charged object, such as your balloon, near a neutral object that is classified as an insulator, than a temporary charge is induced in the neutral object. If the charged object is positive, then electrons in the neutral object will be attracted toward the charged object, creating a temporary imbalance of charges in the neutral object.</span>
Answer:
a) 20 m/s
b) 37.5 m)s
Explanation:
Average speed = total distance ÷ total time
=> (a) average speed of a car that travels 400m in 20s
= 400/20 = 20 m/s
& (b) average speed of an athlete who runs 1500m in 4 minutes (or 4×60=240 seconds)
= 1500/240 = 37.5 m/s
