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FromTheMoon [43]
3 years ago
7

When 28 grams of a metal are heated from 14.4°C to 150°C it takes 23,200). What is the specific heat of the metal?

Chemistry
2 answers:
suter [353]3 years ago
8 0

Answer:

6.11 J/g°C

Explanation:

We need to use the heat equation: q = mCΔT, where q is the amount of heat required in Joules, m is the mass in grams, C is the heat capacity, and ΔT is the change in temperature.

Here, we know q = 23,200 Joules, m = 28 grams, and the ΔT is just the difference of the temperatures: 150 - 14.4 = 135.6°C. Substitute these values to find C:

q = mCΔT

23,200 = 28 * C * 135.6

C = 6.11

Thus, the specific heat is 6.11 J/g°C.

Step2247 [10]3 years ago
4 0

Answer:

6.11 J/g°C

Explanation:

q = mc(delta theta)

23200 = 28 × c × (150 - 14.4)

23200 = 28 × c × 135.6

c = 23200/(28 × 135.6)

c = 6.110408765

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How many molecules are in 3 moles of potassium bromide (KBr)
sattari [20]

Answer:

Your strategy here will be to use the molar mass of potassium bromide,

KBr

, as a conversion factor to help you find the mass of three moles of this compound.

So, a compound's molar mass essentially tells you the mass of one mole of said compound. Now, let's assume that you only have a periodic table to work with here.

Potassium bromide is an ionic compound that is made up of potassium cations,

K

+

, and bromide anions,

Br

−

. Essentially, one formula unit of potassium bromide contains a potassium atom and a bromine atom.

Use the periodic table to find the molar masses of these two elements. You will find

For K:

M

M

=

39.0963 g mol

−

1

For Br:

M

M

=

79.904 g mol

−

1

To get the molar mass of one formula unit of potassium bromide, add the molar masses of the two elements

M

M KBr

=

39.0963 g mol

−

1

+

79.904 g mol

−

1

≈

119 g mol

−

So, if one mole of potassium bromide has a mas of

119 g

m it follows that three moles will have a mass of

3

moles KBr

⋅

molar mass of KBr



119 g

1

mole KBr

=

357 g

You should round this off to one sig fig, since that is how many sig figs you have for the number of moles of potassium bromide, but I'll leave it rounded to two sig figs

mass of 3 moles of KBr

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

360 g

a

a

∣

∣

−−−−−−−−−

Explanation:

<em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em> </em><em>3</em><em>6</em><em>0</em><em> </em><em>g</em><em> </em>

6 0
3 years ago
The expected value for a chemical equation is 47g of water, after an experiment you find that you have 2.58 moles of water. What
strojnjashka [21]
<h3><u>Answer</u>;</h3>

Actual yield = 46.44 g

<h3><u>Explanation;</u></h3>

1 mole of water = 18 g/mol

Therefore;

The experimental yield = 2.58 moles

equivalent to ; 2.58 × 18 = 46.44 g

The theoretical value is 47 g

Percentage yield = 46.44/47 × 100%

                             = 98.8%

The questions asks for actual yield = 46.44 g

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Brrunno [24]

Answer:

po jakiemu to jest XD

Explanation:

po jakiemu to jest XD

3 0
3 years ago
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