Answer:
when mass is 1×10⁴ Kg then density is 5 g/cm³.
when mass is 104 Kg then density is 5.2 × 10⁻² g/ cm³.
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Given data:
mass = 1×10⁴ Kg
volume= w ×l× h = 1×2× 1 = 2 m³
density = ?
first of all we will convert the given volume meter cube to cm³:
we know that
2×1000000 = 2 × 10⁶ cm³
Now we will convert the mass into gram.
1 Kg = 1000 g
1×10⁴ × 1000 = 1 ×10⁷ g
Now we will put the values in the formula,
d = m/v
d = 1 ×10⁷ g / 2×10⁶ cm³
d = 0.5 × 10¹ g/cm³
or
d = 5 g/cm³
If mas is 104 Kg:
104 × 1000 = 104000 g
d= m/v
d = 104000 g / 2×10⁶ cm³
d= 52000 ×10⁻⁶ g/ cm³
d= 5.2 × 10⁻² g/ cm³
Ionic compounds are formed between oppositely charged ions.
A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).
To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.
First empirical formula of binary ionic compound is written between![Zn^{2+} (Positive ion)and F^{-} (Negative ion)](https://tex.z-dn.net/?f=%20Zn%5E%7B2%2B%7D%20%28Positive%20ion%29and%20F%5E%7B-%7D%20%28Negative%20ion%29)
First Formula would be ![ZnF_{2}](https://tex.z-dn.net/?f=%20ZnF_%7B2%7D%20)
Second empirical formula is between ![Zn^{2+}(Positive ion) and O^{2-}(Negative ion)](https://tex.z-dn.net/?f=Zn%5E%7B2%2B%7D%28Positive%20ion%29%20and%20O%5E%7B2-%7D%28Negative%20ion%29)
Second Formula would be ![Zn_{2}O_{2}](https://tex.z-dn.net/?f=Zn_%7B2%7DO_%7B2%7D)
Note : When the subscript are same they get cancel out, so
would be written as ![ZnO](https://tex.z-dn.net/?f=ZnO)
Third empirical formula is between ![Ni^{4+}(Positive ion) and F^{-}(Negative ion)](https://tex.z-dn.net/?f=Ni%5E%7B4%2B%7D%28Positive%20ion%29%20and%20F%5E%7B-%7D%28Negative%20ion%29)
Third Formula would be :![NiF_{4}](https://tex.z-dn.net/?f=NiF_%7B4%7D)
Forth empirical formula is between ![Ni^{4+}(Positive ion)and O^{2-}(negative ion)](https://tex.z-dn.net/?f=Ni%5E%7B4%2B%7D%28Positive%20ion%29and%20O%5E%7B2-%7D%28negative%20ion%29)
Forth Formula would be :
or ![NiO_{2}](https://tex.z-dn.net/?f=NiO_%7B2%7D)
Note- The subscript will be simplified and the formula will be written as
.
The empirical formula of four binary ionic compounds are : ![ZnF_{2}, ZnO, NiF_{4},NiO_{2}](https://tex.z-dn.net/?f=ZnF_%7B2%7D%2C%20ZnO%2C%20NiF_%7B4%7D%2CNiO_%7B2%7D)
B. Developing theories using many lines of evidence