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lys-0071 [83]
3 years ago
7

Is the reaction between methane and oxygen endothermic or exothermic? Explain why we burn fossil fuels, such as natural gas.

Chemistry
1 answer:
vladimir1956 [14]3 years ago
6 0
The thing that governs whether a reaction is exothermic is the energy given out / used up to break / form the bonds in the reaction. 

<span>When two substances react, the bonds in those substances first break up, releasing energy, before re-forming in a different way, taking in energy. The nature of the bonds that are broken up and reformed determines whether more energy is given out (exothermic) or taken in (endothermic)</span>
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Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.
Shtirlitz [24]

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(a) pH = -Log (0.1M) = 1

(b) pH = -Log (10^{-13}M) = 13

(c) pH = -Log (3x10^{-3}M) = 2.5

(d) pH = -Log (4.93x10^{-10}M) = 9.3

(e) pH = -Log (5^{-7}M) = 6.3

Explanation:

To calculate de pH of an acid solution the formula is:

pH = -Log ([H^{+}]) = 1

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

K_{w} =[H^{+} ][OH^{-}]=10^{-14}

clearing the [H^{+} ]

[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}

(d) is a weak base so it is necessary to solve the equilibrium first, knowing Ka=3.24x10^{-8}

The reaction is HClO  →  H^{+} + CO^{-} so the equilibrium is

Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}

clearing the <em>x</em>

{x^{2}={1.62x10^{-17}-3.24x10^{-8}x}

x=[H^{+}]=4.93x10^{-10}

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3 years ago
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