Answer: C. ethanol
The enthalpy of combustion is the amount of heat produced when one mole of ethanol undergoes complete combustion at 25 ° C and 1 atmosphere pressure, yielding products also at 25 ° C and 1 atm.
<u>The enthalpy of combustion of the unknown compound is</u>
ΔH = - 320 kJ / 0.25 mol = - 1280 kJ / mol
<u>To choose a probable compound according to this combustion enthalpy, we must evaluate the deviation in relation to the values reported in the literature for the three probable compounds</u> (methane, ethylene and ethanol). The deviation (e%) will be calculated according to the following equation,
e% = ( | ΔHx - ΔH | / ΔHx ) x 100%
where ΔHx is the enthalpy of combustion of the probable compound.
The following table shows the combustion enthalpies of the probable compounds and their deviation in relation to the enthalpy of ΔH = - 1280 kJ / mol
Compound Enthalpy of combustion (kJ/mol) Deviation
Methane - 890.7 43.8%
Ehylene -1411.2 9.3%
Ethanol -1368.6 6.5%
According to the previous table, we can say that the most probable compound is ethanol, since it has the smallest deviation in relation to the experimental enthalpy value of combustion.
Answer:
No, there is not because it would form H2 instead of methane if hydrogen bonded with itself.
Explanation:
from the shape of methane which is tetrahedral it's evident there's no hydrogen bond only C-H bond.
In order to change celcius to kelvin always add 73 to it leaving you with -195.93
Answer:
<h2>59.1 m</h2>
Explanation:
The height of the object can be found by using the formula
where
p is the potential energy
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
We have the final answer as
<h3>59.1 m</h3>
Hope this helps you
The answer is B. Each chlorine has three non-bonded pairs and one bonded pair of electrons.
I just took the test and it was correct! 5/5 :)
