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2 years ago

Can someone find me the answer please?

Mathematics

2 answers:

inysia [295]2 years ago

8 0

Answer: 6=IDK

Step-by-step explanation:

zloy xaker [14]2 years ago

8 0

Let x be the measure of angle FED, which is the angle in red adjacent to the 108 degree angle. These two angles add to 180, so,

x+108 = 180

x+108-108 = 180-108

x = 72

Angle FED is 72 degrees. So is angle FDE as the two angles have the same angle marker to indicate they are congruent angles.

------------

We know two of the angles of triangle FED are 72 and 72. The missing angle 'u' is added to the two angles and we set the sum equal to 180 to get this equation

72+72+u = 180

Let's solve for the variable 'u' to get

72+72+u = 180

144+u = 180

144+u-144 = 180-144

u = 36

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<h3>Answer: 36</h3>

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Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

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