Sorry im a little late but here's how i did it.
Hope this helps! :)
Answer:
Any expression that equals 5.
Step-by-step explanation:
3 + 2 = 5, so any expression that equals 5 is equivalent to 3+2.
Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Answer:
150
Step-by-step explanation:
15*10
Lets get rid of the 0 for now
15*1
That is 15 added to itself 0 times so it is 15
Now lets put the 0 back
and we will get
150
Answer:
There are many possible solutions. Here are some:
(-2,12) (2,2) (6,1) (10,0) (-6,4)
Step-by-step explanation:
hope it helps
