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tamaranim1 [39]
3 years ago
11

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Mathematics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

1/2x^2-2x

Step-by-step explanation:

x^2+2x+1/2x^4+2x^3-2x^2-2x

(x+1)(x+1)/2x(x+1)(x+1)(x+1)

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What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

3 0
3 years ago
16/ ? = -8 can anyone help plz
erma4kov [3.2K]
I believe the answer is 8
3 0
2 years ago
Read 2 more answers
Two values of x that are roots of xsquared+2x-6=0
xz_007 [3.2K]

The two values of x are

1.65 , -3.65

7 0
3 years ago
Read 2 more answers
24% students in a clan were absent in a day .If 38 students were present ,what is the total strength in the clan
Lemur [1.5K]

Answer:

50 students

Step-by-step explanation:

24% students in a clan were absent in a day .

Hence, the Percentage of students present is calculated as:.

= 100 % - 24 %

= 76%

From the question, we know that:

If 38 students were present ,what is the total strength in the clan

The total strength of the clan = Total number of students. This is calculated as:

76% × x = 38 students.

76/100 × x = 38

76x /100 = 38

Cross Multiply

76x = 38 × 100

x = 3800/76

x = 50 students

5 0
3 years ago
Find the equation of the line that has a slope of -½ and passes through the point (-6,9)
skelet666 [1.2K]

Answer:

y = -1/2x +6

Step-by-step explanation:

We can use the slope intercept form of a line

y = mx+b where m is the slope and b is the y intercept

y = -1/2x +b

Substitute the point into the equation

9 = -1/2 (-6) +b

9 = 3+b

9-3 =b

6 =b

y = -1/2x +6

6 0
3 years ago
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