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3 years ago

What is the prime factorization of 676

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

Answer: 2, 2, 13, 13

Step-by-step explanation: Prime number are numbers that can divide without remainder, This means that 676 is divisible by 2, 2, 13, 13, numbers.

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When solving the equation 4(3x^2 +2)-9=8x^2+7. Emily wrote 4(3x + 2)=8x^2 + 16 as her first step. Which property justifies Emily

vfiekz [6]

Hello :
4(3x² +2)-9=8x²+7 = 4(3x^2 +2)-9 +9 =8x²+7 +9
= 4(3x² + 2)=8x² + 16
(State a reason why1) Addition Property of Equality)

6 0

3 years ago

How do I solve for the fourth term in this sequence?

tatiyna

Answer:

Step-by-step explanation:

d(1) = 13

d(n) = d(n - 1) + 17

where

n is the nth term

To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term

So we have

For the 2nd term

That's d(2)

We have

d(2) = d(2-1) + 17

d(2) = d(1) + 17

But d(1) = 13

d(2) = 13 + 17 = 30

For the 3rd term d(3)

That's

d(3) = d(3 - 1) + 17

d(3) = d(2) + 17

d(3) = 30 + 17 = 47

For the 4th term that's d(4)

We have

d(4) = d(4 - 1) + 17

d(4) = d(3) + 17

d(4) = 47 + 17

We have the final answer as

Hope this helps you

3 0

3 years ago

. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T

lbvjy [14]

Answer:

5/9

Step-by-step explanation:

Number of players = 3

number of times game is repeated = 4

P( any person wins a game ) = 1/3

P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

Note : each player has equal chance of winning

Find the probability that there is at least one person who wins no games

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

P( A1 ∪ A2 U A3 ) = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1 ∩ A3 ) + P( A1 ∩ A2 ∩ A3 )

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

6 0

3 years ago

What is 113.26087 converted in to a fraction.

adelina 88 [10]

Answer:

113.26087 as a fraction equals 11326087/100000

Step-by-step explanation:

To write 113.26087 as a fraction you have to write 113.26087 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

113.26087 = 113.26087/1 = 1132.6087/10 = 11326.087/100 = 113260.87/1000 = 1132608.7/10000 = 11326087/100000

6 0

3 years ago

Read 2 more answers

HELPPP Solve the equation log (2x-3)=2

MaRussiya [10]

Answer:

2.5 or 5/2

Step-by-step explanation:

2x-3=2

2x=5 (both sides plus 3)

x=5/2 or 2.5(divid by 2 on both sides)

8 0

3 years ago