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2 years ago

What is the prime factorization of 676

Mathematics

1 answer:

Blababa [14]2 years ago

4 0

Answer: 2, 2, 13, 13

Step-by-step explanation: Prime number are numbers that can divide without remainder, This means that 676 is divisible by 2, 2, 13, 13, numbers.

You might be interested in

Jorge paid $9 for a book that was originally $12. What was the % discount for the book

anastassius [24]

Answer:

25%

Step-by-step explanation:

12=100%

3=25%

9=75%

6 0

2 years ago

Whats the answer to 8.54 to the nearest tenth

stiks02 [169]

Heres a trick i learned look at the digit your rounding look to your right is it 5 or higher? yeas add 1 more to the one you are rounding if not then you drop the numbers after the one you are rounding so 8.54 is now just 8.5

5 0

3 years ago

3 women push a stalled car. Each woman pushes with a 425 N force. What is the mass of the

iogann1982 [59]

Answer:

1,500 Kg

Step-by-step explanation:

Formual for froce is given by

force = mass * acceleration

Force exerted by 1 woman = 425 N

no. of women exerting force = 3

Force exerted by 3 woman = 425 * 3 N = 1275 N

Acceleration produced by 1275 N force = 0.85 m/s^2

Using formula force = mass * acceleration

1275 = mass * 0.85 m/s^2

=> mass = 1275/ 0.85 m/s^2 = 1,500 Kg

Thus, mass of car is 1,500 Kg.

8 0

2 years ago

I need some help with math

Irina18 [472]

Answer:

$(y-7)^2+(x-2)^2=16$

and

$(x+2)^2+(y-15)^2 = 9$

Step-by-step explanation:

The standard equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where the coordinate (h,k) is the center of the circle.

Second Problem:

We can start with the second problem which uses this info very easily.
(h,k) in this problem is (-2,15) simply plug these into the equation. $(x--2)^2+(y-15)^2=r^2$ .
We can also add the radius 3 and square it so it becomes 9. The equation.
This simplifies to $(x+2)^2+(y-15)^2 = 9$ .

First Problem:

The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
$y^2-14y+x^2-4x+37=0$ first subtract 37 from both sides so the equation is now $y^2-14y+x^2-4x=-37$ .
$y^2-14y+x^2-4x+37=0$ by adding $(-\frac{b}{2a} )^2$ to both the x and y portions of this equation you can complete the squares. $(-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2$ and $(-\frac{-4}{2(1)})^2$ which equals 49 and 4.
Add 49 and 4 to both sides and the equation is now: $y^2-14y+49+x^2-4x+4=-37+49+4$ You can simplify the y and x portions of the equations into the perfect squares or factored form $(y-7)^2$ and $(x-2)^2$ .
Finally put the whole thing together. $(y-7)^2+(x-2)^2=16$ .