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Juliette [100K]
3 years ago
12

If you travel south from the equator to 25°S, how far will you have to travel? The circumference of the earth is approximately 4

0,000 km or 24, 900 mi.
Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

2,777.8 km or 1,729.2 mi

Step-by-step explanation:

first think about how many degrees would you travel if you wanted to do a whole circunference always going south: it would take 360 degress to complete a circunference.

Then you can use a rule of three to find the answer:

If the whole circunference is 40,000km and in degrees is 360, then how much 25 degrees would be?

x= \frac{25}{360}*40,000

x= 2777.8

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What is 1/4 times 268?
tia_tia [17]
1/4 is equal to 0.25. so you can multiply 0.25 and 268 to get your answer of 67
8 0
3 years ago
A 4-Pack of coffee drinks is $6.90.what is the cost per bottle.
MakcuM [25]

Answer:

$ 1.725

Step-by-step explanation:

4 Pack of coffee = $ 6.90

1 Pack of coffee = $ 6.90 / 4 = $ 1.725

( The word per means " 1 " )

6 0
2 years ago
Read 2 more answers
Find the x and y intercepts for the equation 2x + 7y = 42.
o-na [289]

Answer:

see explanation

Step-by-step explanation:

Given

2x + 7y = 42

To find the x- intercept let y = 0 in the equation and solve for x

2x + 7(0) = 42, that is

2x = 42 ( divide both sides by 2 )

x = 21 ← x- intercept or (21, 0 )

To find the y- intercept let x = 0 in the equation and solve for y

2(0) + 7y = 42 , that is

7y = 42 ( divide both sides by 7 )

y = 6 ← y- intercept or (0, 6 )

6 0
3 years ago
Oscar drew the image of a
trasher [3.6K]

Answer:

When we have a point (x, y) and we do a reflection over a given line, we know that the new point (x', y') will be at the same distance from the line as our initial point (x,y).

Now, in this case, we have a reflection over the line y = -1. (this line is parallel to the x-axis)

But in the image, we can see that the reflected triangle is drawn in the other side of the y-axis, this means that the reflection was made in a line parallel to the y-axis.

Then the mistake that Oscar did is that he reflected over the wrong line, seems that he reflected the triangle over the line x = -1 instead of the line y = -1.

7 0
3 years ago
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
3 years ago
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