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Juliette [100K]
3 years ago
12

If you travel south from the equator to 25°S, how far will you have to travel? The circumference of the earth is approximately 4

0,000 km or 24, 900 mi.
Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

2,777.8 km or 1,729.2 mi

Step-by-step explanation:

first think about how many degrees would you travel if you wanted to do a whole circunference always going south: it would take 360 degress to complete a circunference.

Then you can use a rule of three to find the answer:

If the whole circunference is 40,000km and in degrees is 360, then how much 25 degrees would be?

x= \frac{25}{360}*40,000

x= 2777.8

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The circle C has centre A(2,1) and passes through the point B(10,7). Find and equation for C
Semmy [17]
The equation of a circle:
(x-h)^2+(y-k)^2=r^2
(h,k) - the coordinates of the centre
r - the radius

A(2,1) - \hbox{the centre} \\
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3 years ago
Yesterday, 20 guests at a hotel called for room service, and 60 guests did not call for room service. What percentage of the gue
Neko [114]

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6 0
2 years ago
What is the sum of <br> 4 1/2 + 1 3/5 in simplest form ?
olga2289 [7]

Answer:

Step-by-step explanation:

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Decimal Form:

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6 0
3 years ago
The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough
liberstina [14]

Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0
2 years ago
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