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Leni [432]
3 years ago
12

What is the GCF of 2x^3-7x^2+3x

Mathematics
2 answers:
natulia [17]3 years ago
6 0

2x3 – 7x2 + 3x

The GCF is

the answer is C.X

timurjin [86]3 years ago
3 0
The GCF to this question is 1x.
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A shopper bought 15 apples and 5 oranges. Which statement describes the ratio of apples to
dexar [7]

Answer:

15:5 is the ratio of apples to oranges and 5:15 if reverse

5 0
4 years ago
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

 \hat p=\frac{232}{400}=0.58

Compute the test statistic value as follows:

 z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
4 years ago
Which of the following statements is true for the logistic differential equation?
solong [7]

Answer:

All of the above

Step-by-step explanation:

dy/dt = y/3 (18 − y)

0 = y/3 (18 − y)

y = 0 or 18

d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)

d²y/dt² = dy/dt (-y/3 + 6 − y/3)

d²y/dt² = dy/dt (6 − 2y/3)

d²y/dt² = y/3 (18 − y) (6 − 2y/3)

0 = y/3 (18 − y) (6 − 2y/3)

y = 0, 9, 18

y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.

y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.

8 0
3 years ago
Please help I with give Brainiest if correct
padilas [110]

Answer:

  Perimeter of the rectangle  = 6 x +20

 Perimeter of the rectangle  = 0<em> x² + 6 x + 20</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the length of the rectangle = 2x +3

Given that the width of the rectangle = x +7

Perimeter of the rectangle   = 2(length + width)

<u>Step(ii):-</u>            

  Perimeter of the rectangle   = 2(length + width)

                                                  = 2(2 x +3 + x+7)

                                                 =  4x +6+2x+14

                                                 = 6 x +20        

<u><em>Final answer:-</em></u>

 Perimeter of the rectangle  = 6 x +20

 Perimeter of the rectangle  = o x² + 6 x + 20

7 0
3 years ago
Garth is packing boxes with books. The list shows how many books are in each of 10 boxes.
8_murik_8 [283]

:Answer: The answer is C on Edge

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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